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Maximum range problem, please help!

 
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Feb28-12, 03:50 PM   #1
 

Maximum range problem, please help!


Hey guys,

I was hoping somebody might help me; I'm really confused. I obtained the formula for distance, which is this:

d=[(2[v_0]^2(cos[alpha])sin([alpha-beta])]/gcos^2(beta)

And the derivative for distance, which is this:

derivative of d with respect to alpha=0=(2[v_0]^2)/(gcos^2(beta))*(-sin(alpha)sin(alpha-beta)+cos(alpha)cos(alpha-beta))*cos(2alpha-beta)

I was trying to see what alpha would be for maximum range, but I have no idea where the very end term on the right comes from: cos(2alpha-beta). Could somebody please me? Thank you.

David
 
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Feb28-12, 04:17 PM   #2
 
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Hey David!
Quote by delve View Post
d=[(2[v_0]^2(cos[alpha])sin([alpha-beta])]/gcos^2(beta)

And the derivative for distance, which is this:

derivative of d with respect to alpha=0=(2[v_0]^2)/(gcos^2(beta))*(-sin(alpha)sin(alpha-beta)+cos(alpha)cos(alpha-beta))*cos(2alpha-beta)
No, that *cos(2α-β) at the end must be a misprint for =cos(2α-β) …
cos(A+B) = cosAcosB - sinAsinB
 
Feb28-12, 10:06 PM   #3
 
Thank you very much Tiny-Tim! That was exactly what I needed! :D
 
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