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Does Clifford algebra solve both QFT and GR |
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| Feb13-12, 11:27 AM | #1 |
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Does Clifford algebra solve both QFT and GR
I noticed a few sources that seem to indicate that Clifford algebra may be used in both QFT and GR. I've seen where the Clifford algebra is a type of associative algebra that generalizes the real numbers, complex numbers, quaternions, and octonions, see Wikipedia on Clifford Algebra. And I've seen where the complex numbers, quaternions, and octernions can be used in the description for the U(1), SU(2), SU(3) symmetries of the Standard Model, see this article, and this book. However, I've also seen where the Clifford algebra can be used in an alternative description of differential geometry used in the formulation of GR, see this book for example.
So my question is does this common algebra allow us to derive GR in terms of QFT or visa versa? Or if we could justify the use of the complex numbers, quaternions, octonions, and the Clifford algebra by some other means, could we derive both QFT and GR from that common justification of the algebra? What more information or constraints would be needed to do so? |
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| Feb14-12, 03:54 PM | #2 |
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I'm trying to decide whether I should research the Clifford algebra and how it applies to physics. I'm looking to get a sense of how valid is the application of Clifford algebra in physics. Is there a consenses that Clifford algebra, quaternions, and octonions are indeed fundamental or at least have a valuable use?
If the use of these algebras is valid in physics, then I have to wonder... Since the Clifford algebra is used in differential geometry, and quaterions and octonions are used in the SM, then can the quaternions and octonions be used to contrain the Clifford algebra in such a way in differential geometry as to product GR if the SM is assumed? Or is it more the case that the Clifford algebra is used on the metric whereas the quaternion and octonions are used on wavefunctions, which is a totally different animal? Any insight would be appreciated. Thanks. |
| Feb22-12, 12:46 AM | #3 |
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[QUOTE=friend;3764308]I'm trying to decide whether I should research the Clifford algebra and how it applies to physics...QUOTE]
What a strange question! Of course Clifford (geometric) algebra does apply to physics! Just think about spinors, Dirac equation... |
| Mar1-12, 12:51 PM | #4 |
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Does Clifford algebra solve both QFT and GRSo when they use the quaternions and octonions in the SM, do they use the algebra to establish commutation relation between fields? How is the Clifford algebra used in GR? Is it used on connection fields perhaps? Does it establish commutation relations, or perhaps the Bianchi identity, what? Thanks. |
| Mar1-12, 01:33 PM | #5 |
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Clifford algebras are particularly necessary for understanding spinor representations and spin groups. Depending on what you're interested in studying, they could be important (a good knowledge of the mathematical underpinnings of SM and QFT will require knowledge of Clifford algebras). I'd say that quaternions (and octonions) are less important: quaternions offer an alternative to the tensor formulation of GR, and are not something I'd concern myself with on an initial read through.
I would certainly get up to speed on your linear algebra and group theory (in particular Lie groups and Lie algebras which are widespread in particle physics) before I'd worry about Clifford algebras and quaternions. |
| Mar1-12, 03:05 PM | #6 |
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| Mar2-12, 12:22 AM | #7 |
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| Mar2-12, 04:44 PM | #8 |
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You get everything you need to beginn with and if you are patient, at the very end of the book, a part of the answer to your initial question. |
| Mar3-12, 11:12 AM | #9 |
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But from what I can tell from what I've seen on the Net, clifford algebra is used either for geometry or for the SM in the form of quaternions and octonions. What I don't see is anyone connecting the two. Is this because the algebra operates on two different objects that can't be connected in some way? |
| Mar3-12, 11:25 AM | #10 |
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For example, is there a connection between spin foam networks of LQG and the spinors derived using clifford algebra?
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| Mar3-12, 11:59 AM | #11 |
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But I just guess that the answer is: some where yes. Good luck http://arxiv.org/pdf/1201.2120v1.pdf |
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