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Find final angular velocity. |
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| Mar5-12, 11:34 PM | #18 |
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Find final angular velocity. |
| Mar5-12, 11:42 PM | #19 |
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http://www.real-world-physics-proble...ollision_8.png like this, i know all my momentum. but 150 does not equal -150 un less you set the equation to 0=150-150 which equals 0. But what happened to the angular velocity??? don't i need to find like a magnitude in angular in velocity??
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| Mar5-12, 11:48 PM | #20 |
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![]() If you have two equal mass objects traveling with the same speeds in a head-on collision and they stick together, what's their final velocity? By the way, the equation shown in your link is for elastic collisions, not inelastic. In a perfectly inelastic collision the two objects fuse -- m1+m2. |
| Mar5-12, 11:52 PM | #21 |
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0? but this 2 objects had different speeds! does i mean that doesn't matter how fast the objects are moving , when they stick together they both have 0 velocity??
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| Mar5-12, 11:54 PM | #22 |
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| Mar5-12, 11:59 PM | #23 |
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oh so it was only finding the moments of inertia to calculate angular momentum and use conservation of energy of inelastic collision??? that was it? ok now for part 2 i know the answer is 338 J
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| Mar6-12, 12:01 AM | #24 |
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If i sum up both of my KE rot they give me the answer, but here is my doubt why do i have to sum it up? don't I have to find the KE total and subtract that from KE rot f to get the kinetic energy lost??
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| Mar6-12, 12:03 AM | #25 |
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| Mar6-12, 12:07 AM | #26 |
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KE total is = 225J+112.5J
KEf=0 ??? |
| Mar6-12, 12:10 AM | #27 |
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| Mar6-12, 12:17 AM | #28 |
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LOL no. So the KEf is 0 after all? I thought it was 0 because after the collision they both have no kinetic energy because they have no velocity. They both come to a stop. Don't know if my reason is indeed correct.
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| Mar6-12, 12:20 AM | #29 |
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| Mar6-12, 12:21 AM | #30 |
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thanks man! :D
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