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Secant line in Fermat's Theorem |
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| Mar8-12, 12:07 PM | #1 |
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Secant line in Fermat's Theorem
I'm trying to understand something in Fermat's Theorem. I can't really phrase it in words, but I will write what my textbook says.
Apparently if [tex] \lim_{x→c}\frac{f(x)-f(c)}{x-c} > 0 [/tex] then there exists an open interval (a,b) containing c such that [tex] \frac{f(x)-f(c)}{x-c} > 0 [/tex] for all c in that interval. How does this follow from the definition of the derivative? I appreciate all help. Thanks! |
| Mar8-12, 02:00 PM | #2 |
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That is a general property of limits. If$$
\lim_{x\rightarrow c}g(x) = L > 0$$then there is an open interval ##I## containing ##c## on which ##g(x)>0##. It comes directly from the ##\epsilon - \delta## definition of limit. |
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