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Angle help!

by Taylor_1989
Tags: angle
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Taylor_1989
#1
Mar8-12, 08:26 AM
P: 106
1. The problem statement, all variables and given/known data
Calculate the angle between the ray PQ and the ray RS

Anouther ray TQ also strikes the surface at Q. The refractive index of the glass is 1.50


2. Relevant equations

c= 1/ refractive index

3. The attempt at a solution
The answer on my sheet say it is 20 degree, I have had to different attempts which have give me 20.9 and 21.6 neither which i think is right. I cal the 1st on by: 1/1.50=41.8/2 which gave 20.9 and the second by 85-41.8/2 which gave 21.6. I took the refractive index from a question further down, which I have put in, but I don't need help with that question. As this is in my book and taken from a past paper, I don't know that If i looked at the exam paper, I could just measure the angle. But as it says calculate I assume, I have to use the equations
Attached Thumbnails
Angle.jpg  
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Taylor_1989
#2
Mar8-12, 08:27 AM
P: 106
*Another
issacnewton
#3
Mar9-12, 01:02 AM
P: 610
hi, your diagram is not clear. there is no point P in the diagram. its difficult to understand the problem with the given diagram. Taylor, if your problem can't be understood by people here, there is less chance that people will help you. always post questions in clear manner
so that even a baby can understand it...

Taylor_1989
#4
Mar9-12, 05:08 AM
P: 106
Angle help!

Quote Quote by issacnewton View Post
hi, your diagram is not clear. there is no point P in the diagram. its difficult to understand the problem with the given diagram. Taylor, if your problem can't be understood by people here, there is less chance that people will help you. always post questions in clear manner
so that even a baby can understand it...
Thanks for the response, I wonder why I haven't has a response, I will try and draw a more clear diagram.
Taylor_1989
#5
Mar9-12, 05:26 AM
P: 106
Right I have managed to, get a copy of the exam paper, question. I have attached, so I hope this helps people ans my question.

Many thanks.
Attached Thumbnails
New angle.jpg  
Taylor_1989
#6
Mar9-12, 08:27 AM
P: 106
Right, I think I a seen where I have gone wrong, after searching on the internet for about 4hrs "bad times". The question is about something called deviation? As I understand deviation is the difference between the sin i and sin r (not refractive index). So I am right in working out the question this way: 90 degree - 85 degree= 5 degree, so that is the angle of deviation for 1 half? Then I did 85 * 2= 170 degree and 5*2= 10, 170-10= 160 so the 180-160=20.

If possible could someone verify this, and give me a better explanation on deviation if there is one as deviation is not included much in my books.
BruceW
#7
Mar9-12, 10:20 AM
HW Helper
BruceW's Avatar
P: 3,448
I don't know about deviation, but I did get the right answer. And I'm not sure how you got the answer, so I'll just try to help from the beginning.

Firstly, there is an incident ray PQ, and reflected ray QR. And it gives you the incident angle (which is measured from the normal N). So what can you say about the angle of the reflected ray? (again measured from the normal N)
Taylor_1989
#8
Mar9-12, 10:57 AM
P: 106
Quote Quote by BruceW View Post
I don't know about deviation, but I did get the right answer. And I'm not sure how you got the answer, so I'll just try to help from the beginning.

Firstly, there is an incident ray PQ, and reflected ray QR. And it gives you the incident angle (which is measured from the normal N). So what can you say about the angle of the reflected ray? (again measured from the normal N)
I can sort of see you coming from, but 100% could you please expand, or show the exact calculation, so I can work back from how you worked it out. Also what are you counting as the normal? The N and M on the diagram.

I do apologize if this is a bit of a stupid question, but I am self taught, so I only understand what I have read.
issacnewton
#9
Mar9-12, 11:06 AM
P: 610
taylor, angle of incidence is same as angle of reflection. that is one of the laws of geometric optics.. so can you see which one is angle on incidence and which one is angle reflection at point Q

Edit: http://en.wikipedia.org/wiki/Angle_of_incidence
issacnewton
#10
Mar9-12, 11:18 AM
P: 610
angle of incidence is PQN, since QN is normal at point Q. now whats angle of reflection ?
Taylor_1989
#11
Mar9-12, 11:31 AM
P: 106
Quote Quote by issacnewton View Post
angle of incidence is PQN, since QN is normal at point Q. now whats angle of reflection ?
Yer my bad, I was looking at the question thinking it was a lot harder than it looks. I completely forgot about the incident = reflection. Rookie mistake, least I learnt from this mistake, to read the question more carefully.

Thanks for the help, probs would have been stuck on this for a long time, until I realized where I was going wrong.
issacnewton
#12
Mar9-12, 11:41 AM
P: 610
so whats the answer you got ?


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