
#1
Mar812, 08:26 AM

P: 106

1. The problem statement, all variables and given/known data
Calculate the angle between the ray PQ and the ray RS Anouther ray TQ also strikes the surface at Q. The refractive index of the glass is 1.50 2. Relevant equations c= 1/ refractive index 3. The attempt at a solution The answer on my sheet say it is 20 degree, I have had to different attempts which have give me 20.9 and 21.6 neither which i think is right. I cal the 1st on by: 1/1.50=41.8/2 which gave 20.9 and the second by 8541.8/2 which gave 21.6. I took the refractive index from a question further down, which I have put in, but I don't need help with that question. As this is in my book and taken from a past paper, I don't know that If i looked at the exam paper, I could just measure the angle. But as it says calculate I assume, I have to use the equations 



#2
Mar812, 08:27 AM

P: 106

*Another




#3
Mar912, 01:02 AM

P: 606

hi, your diagram is not clear. there is no point P in the diagram. its difficult to understand the problem with the given diagram. Taylor, if your problem can't be understood by people here, there is less chance that people will help you. always post questions in clear manner
so that even a baby can understand it... 



#4
Mar912, 05:08 AM

P: 106

Angle help! 



#5
Mar912, 05:26 AM

P: 106

Right I have managed to, get a copy of the exam paper, question. I have attached, so I hope this helps people ans my question.
Many thanks. 



#6
Mar912, 08:27 AM

P: 106

Right, I think I a seen where I have gone wrong, after searching on the internet for about 4hrs "bad times". The question is about something called deviation? As I understand deviation is the difference between the sin i and sin r (not refractive index). So I am right in working out the question this way: 90 degree  85 degree= 5 degree, so that is the angle of deviation for 1 half? Then I did 85 * 2= 170 degree and 5*2= 10, 17010= 160 so the 180160=20.
If possible could someone verify this, and give me a better explanation on deviation if there is one as deviation is not included much in my books. 



#7
Mar912, 10:20 AM

HW Helper
P: 3,337

I don't know about deviation, but I did get the right answer. And I'm not sure how you got the answer, so I'll just try to help from the beginning.
Firstly, there is an incident ray PQ, and reflected ray QR. And it gives you the incident angle (which is measured from the normal N). So what can you say about the angle of the reflected ray? (again measured from the normal N) 



#8
Mar912, 10:57 AM

P: 106

I do apologize if this is a bit of a stupid question, but I am self taught, so I only understand what I have read. 



#9
Mar912, 11:06 AM

P: 606

taylor, angle of incidence is same as angle of reflection. that is one of the laws of geometric optics.. so can you see which one is angle on incidence and which one is angle reflection at point Q
Edit: http://en.wikipedia.org/wiki/Angle_of_incidence 



#10
Mar912, 11:18 AM

P: 606

angle of incidence is PQN, since QN is normal at point Q. now whats angle of reflection ?




#11
Mar912, 11:31 AM

P: 106

Thanks for the help, probs would have been stuck on this for a long time, until I realized where I was going wrong. 



#12
Mar912, 11:41 AM

P: 606

so whats the answer you got ?



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