|Mar9-12, 04:54 AM||#1|
Find the size of Driving couple, if given the power?
1. The problem statement, all variables and given/known data
Not really HW, just revision.
A shaft rotating at 3000 revolutions per minute is transmitting power of 10000 watts. find the size of the driving couple.
2. Relevant equations
Total wrk done by couple = 2.F.r.θ
Work = Torque . θ ( angle of rotation )
Power = work done / time
3. The attempt at a solution
60 seconds = 3000 revolutions
1 second = ?
Ans came to 50
Using ω = 2∏f resulted in ω = 100∏
Power = (Torque . θ)/t where θ/t = ω
Subject of the formula gave me 9.54 as an answer. When it should be 32Nm
What have I done wrong?
|Mar9-12, 05:02 AM||#2|
hi alec433lawrid! welcome to pf!
how did you get 9.54 ?
|Mar9-12, 05:14 AM||#3|
Oh wow!, I am such a noob!
Sorry for wasting your time.
I did have the correct answer. ie my reasoning was correct. My calculator skills on the other hand let me down :(
I did 10000 / 100∏
when i should have done 10000 / (100 * ∏ )
It was a stupid mistake....
|angluar velocity, power, torque|
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