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Value of g near a black hole (revisited) 
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#91
Mar1212, 08:41 PM

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#92
Mar1212, 08:58 PM

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If you and your partner are both falling into the black hole, then from your point of view, you and your partner are stationary and the event horizon is rushing towards you at the speed of light. You see your partner 10 feet in front of you at all times. The image you see has been delayed 10 nanoseconds; you see where your partner was 10 ns ago. At exactly the moment you reach the event horizon (i.e. at a distance of zero, not a distance of 1 planck length) you see, 10 feet in front of you, what your partner was doing 10 ns earlier, which was crossing the event horizon. (10 ns ago the event horizon was 10 ft in front of you, as was your partner.) This illustrated in the lefthand spacetime diagram below. If you decide at the last minute to brake and hover at a small fixed distance outside the event horizon, you see your partner's image slow down, redshift and darken and never actually cross the horizon. This illustrated in the righthand spacetime diagram below. 


#93
Mar1212, 11:12 PM

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I think you are forgetting the tidal forces between them. 


#94
Mar1212, 11:20 PM

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#95
Mar1312, 09:28 AM

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#96
Mar1312, 09:52 AM

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I think this thread is dead. 


#97
Mar1312, 10:24 AM

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If there's distance between them and you are one plank length away from the horizon then 'As you approach you see objects in front of you crossing the horizon, and you're seeing light from the other side of the event horizon. When you move away the light from previous observers moves back across the event horizon'. I thought there was "plenty of room". The only other alternative is that they all pile up at the horizon.



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