Register to reply

Integration constant question

by wumple
Tags: constant, integration
Share this thread:
Mar13-12, 12:04 PM
P: 60

I thought that if you integrate with limits, you don't include a constant, but if you don't integrate with limits (indefinite), there is a constant. But my book gives the example (all functions are single variable functions, initially of x but then changed to s for the integration):

[tex] f' = \frac{1}{2}(\phi'+\frac{\psi}{c}) [/tex]


[tex] f(s) = \frac{1}{2}\phi(s) + \frac{1}{2c}\int_0^s\psi + A [/tex]

What's going on here?
Phys.Org News Partner Science news on
What lit up the universe?
Sheepdogs use just two simple rules to round up large herds of sheep
Animals first flex their muscles
Mar13-12, 12:20 PM
Sci Advisor
HW Helper
mathwonk's Avatar
P: 9,481
the first statement implies the second. I.e. if all you know about f is its derivative, then you can only know f up to an additive constant.

try to get away from memorizing mindless rules like the (flawed) ones you stated. learn what the concepts mean.

Register to reply

Related Discussions
Why no constant of integration for the integration factor? Differential Equations 2
Importance of adding the constant of integration. Differential Equations 8
Confusion about the constant of integration and bounds Calculus 1
The Constant of Integration Calculus & Beyond Homework 2
Integration with constant of proportionality Calculus & Beyond Homework 2