Register to reply

Complex Solutions

by Rubik
Tags: complex, solutions
Share this thread:
Rubik
#1
Mar12-12, 09:31 PM
P: 97
1. The problem statement, all variables and given/known data
Find all complex solutions to [itex]\bar{z}[/itex] = z


2. Relevant equations

z = x + iy and [itex]\bar{z}[/itex] = x - iy

3. The attempt at a solution
What does it mean by find all complex solutions?

[itex]\bar{z}[/itex] = z
0 = x + iy - x + iy
0 = 2iy
1. The problem statement, all variables and given/known data



2. Relevant equations



3. The attempt at a solution
Phys.Org News Partner Science news on Phys.org
FIXD tells car drivers via smartphone what is wrong
Team pioneers strategy for creating new materials
Team defines new biodiversity metric
aanandpatel
#2
Mar12-12, 09:36 PM
P: 16
Two complex numbers are only equal if their real parts are equal and their imaginary parts are equal so you may have to equate real and imaginary parts to find the values of x and y.
SammyS
#3
Mar12-12, 10:59 PM
Emeritus
Sci Advisor
HW Helper
PF Gold
P: 7,808
Quote Quote by Rubik View Post
1. The problem statement, all variables and given/known data
Find all complex solutions to [itex]\bar{z}[/itex] = z


2. Relevant equations

z = x + iy and [itex]\bar{z}[/itex] = x - iy

3. The attempt at a solution
What does it mean by find all complex solutions?

[itex]\bar{z}[/itex] = z
0 = x + iy - x + iy
0 = 2iy
If 0 = 2iy, then ...
1. What must x be for this to be true?

2. What must y be for this to be true?

aanandpatel
#4
Mar13-12, 06:45 AM
P: 16
Complex Solutions

2y = 0 and x=0
HallsofIvy
#5
Mar13-12, 06:52 AM
Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 39,552
How do you arrive at "x= 0" from an equation that does not have an "x" in it??
NewtonianAlch
#6
Mar13-12, 07:07 AM
P: 446
Well the basic form is x + iy, so we know the x part of the complex number must be equal to zero if it's not there.
SammyS
#7
Mar13-12, 08:47 AM
Emeritus
Sci Advisor
HW Helper
PF Gold
P: 7,808
Quote Quote by NewtonianAlch View Post
Well the basic form is x + iy, so we know the x part of the complex number must be equal to zero if it's not there.
Look at the equation (from post #1):
0 = x + iy - x + iy
Is there any x that will not satisfy this, if y=0 ? If there is such an x, what is it ?
aanandpatel
#8
Mar14-12, 12:28 AM
P: 16
Yes when I say x=0 it means that the 'real part' of the solution is 0
HallsofIvy
#9
Mar14-12, 05:57 AM
Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 39,552
Yes, and as you have been told repeatedly, that is wrong. The equation 2iy= 0 does NOT say "x= 0 because x isn't there". The fact that x is not in that equation means that the equation does not tell you anything about x. Suppose z= 4+ 0i. What is [itex]\overline{z}[/itex]?
HallsofIvy
#10
Mar14-12, 06:08 AM
Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 39,552
Good point. I really hadn't thought of that! Okay, how about a simple sequence of real numbers?


Register to reply

Related Discussions
Complex Solutions Calculus & Beyond Homework 7
Complex Solutions Calculus & Beyond Homework 1
Complex Solutions General Math 4
COMPLEX SOLUTIONS help! Calculus 6
Complex solutions Precalculus Mathematics Homework 3