Powers with rational exponents: write as single power then evaluate. (Review My Work)

1. The problem statement, all variables and given/known data
Write as a single power, then evaluate:
a) (-32)^3/5 x (-32)^-4/5 / (-32)^2/5

b) 4096^3/6 / 4096^2/3 x 4096^5/6

2. Relevant equations

3. The attempt at a solution

a) (-32)^3/5 x (-32)^-4/5 / (-32)^2/5
= (-32)^3/5+(-4/5)-2/5
= -32^-3/5

b) 4096^3/6 / 4096^2/3 x 4096^5/6
= 4096^(9-8+10)/12
= 4096^11/12

I'm not so sure of where to go from here.
 Your first answer is right :-) Second needs some review. Remember (x^a*x^b)/(x^c*x^d) Is x^(a+b-c-d) So its 4096^(3/6-2/3-5/6) You have made a mistake by writing 4096^({9}-8-10)/12 It shouldn't be 9 in the curly brackets i put{} :-). Also factorise 4096. Write it in power of primes. For eg 400=2^4*5^2 So (400)^(1/2) Is [(2^4)*(5^2)]^(1/2) So its (2^2)*(5) which gives 20.
 Oh man I copied down the wrong problem. I'm so sorry. It was supposed to be: 4096^3/4 / 4096^2/3 x 4096^5/6 I got the common denominator which would been 12. That is how I got 4096^(9-8+10)/12 = 4096^11/12 am I still incorrect?

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