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Velocity - time home work check |
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| Mar22-12, 10:36 PM | #1 |
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Velocity - time home work check
1. The problem statement, all variables and given/known data
A car accelerates from 0 to 30m s ^-1 in 5.0 seconds, travels at a constant 30m s^-1 for 15.0 seconds and then brakes to a stop in 10.0 seconds. 1) calcualte the acceleration (assumed constant) in each section of the motion. 2) calculate distance travelled 3) what is 30m s^-1 in km/h? 2. Relevant equations a= change in velocity / change in time d(t) = v_0 x t + (a/2)t^2 3. The attempt at a solution a=(30-0)/5 = 6 m/s d(t) = 0 x 5 +(6/2_ x 5^2 = 75m a=(30-30)/15 = 0 m/s^2 d(t) = 30 x 15 + (0/2) x 15^2 = 450m a=(0-30)/10 = -3m/s^2 d(t) = 30 x 10 + (-3/2) x 10^2 = 150m |
| Mar22-12, 11:07 PM | #2 |
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Looks OK!
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| Mar22-12, 11:54 PM | #3 |
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Thanks so much! I'm working so slowly trying to get it right. Thanks again, the feedback is a boost!
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| distance, time, velocity |
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