
#1
Mar2712, 06:45 PM

P: 17

1. The problem statement, all variables and given/known data
A line passes through the point (1, 4) and is perpendicular to the line 3x + 2y – 6 = 0. Determine a scalar equation for the line. Was also given this: Find a vector which is normal to the line and then use the dot product of this vector and P0P. 2. Relevant equations scalar equation: ax+by+c=0 3. The attempt at a solution i'm not sure if this gets me anywhere but i turned the scalar equation into a vector equation: Random point on line: (0,3), therefore vector equation r=(0,3)+t(2,3) Not sure where i can go from here, i just know i have to find a line perpendicular to 3x + 2y  6 =0 that goes through the point (1, 4) 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution 



#2
Mar2712, 07:19 PM

HW Helper
Thanks
PF Gold
P: 7,197

Remember that a the coefficients of 3x+2y=6 give you a normal vector to the line. So use <3,2> for your direction vector and (1,4) for your point. Write the vector equation using those and eliminate the parameter to get your scalar equation.




#3
Mar2712, 09:44 PM

P: 17

Okay thank you very much



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