Black Body radiation

by dsdsuster
Tags: black, body, radiation
dsdsuster is offline
Apr9-12, 01:56 PM
P: 30
Can someone help explain what's going on here?

Specifically the part about how radiated power is greater than perpendicular power.
I also don't understand why the power is being averaged over the various angles. Doesn't it make more sense to add the powers from light arriving at different angles to get the total energy transmitted?
Phys.Org News Partner Physics news on
Physicists design quantum switches which can be activated by single photons
'Dressed' laser aimed at clouds may be key to inducing rain, lightning
Higher-order nonlinear optical processes observed using the SACLA X-ray free-electron laser
mikeph is offline
Apr9-12, 05:31 PM
P: 1,200
I can't follow this very well, nothing is defined and I can't work out the overall goal.

I think it's saying that the radiation going through the specified surface from some angle is not perpendicular, so you need to use cos(theta) to find the perpendicular component of the vector.

Register to reply

Related Discussions
black body radiation Introductory Physics Homework 0
Black Body radiation Atomic, Solid State, Comp. Physics 4
Black body radiation Quantum Physics 1
Black body radiation, need help Introductory Physics Homework 2
Black body Radiation Introductory Physics Homework 2