# Finding the flux of an electrix field

by failexam
Tags: electrix, field, flux
 P: 319 1. The problem statement, all variables and given/known data A charge q sits in the back corner of a cube, as shown in the attachment. What is the flux of E through the shaded side? 2. Relevant equations 3. The attempt at a solution I know that I need the surface integral of E over the shaded area, but the problem is with choosing the proper coordinates and the origin. Please help out this poor guy! Attached Thumbnails
 P: 125 Gauss's law finds the charge ENCLOSED, So one way to do this question is to enclose the charge by surrounding the charge by another 7 boxes. Then you can compute the integral as the charge is now enclosed. There will be 24 faces after surrounding the charge, so integral will produce a flux 24 times the flux through one face (seeing as you only need the flux through one face) and I think you can take it from there, I've seen this question in griffiths electrodynamics before I think

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