Acceleration as a function of time and positionby Ali, Ahmed Tags: acceleration, function, position, time 

#1
Apr2612, 11:29 AM

P: 21

I'm quite curious as to whether there is an equation (whether it be in scalar, vector, or tensor form) that defines the acceleration of a particle as a function of the three space coordinates and time.
My curiosity arose when I was thinking of the one dimensional equation: a = v*(dv/dx); where the acceleration and velocity are only defined in the xdirection. I thought the generalization to three dimensions would be: a = v_{x}*(dv_{x}/dx)i + v_{y}*(dv_{y}/dy)j + v_{z}*(dv_{z}/dz)k To include the time variable I thought it might just be the material derivative of acceleration (like in fluid mechanics). These assumptions are just based on my gut feeling (I have done no derivation whatsoever). Is there an actual equation? 



#2
Apr2612, 02:49 PM

P: 784

Well I don't know if there is a general equation (which there probably is), but in one dimension you are just looking for the second derivative of the equation of motion of the body.
In more than one dimension you can just split it up into an arbitrary amount of simultaneous parametric equations, and once again its the second derivative of each individual equation. Once again there might be a general rule, but what I just said above will definitely work. 



#3
Apr2612, 04:15 PM

P: 269

but for 3 dimensions, instead of x we use R so dV/dt=(dR/dt)(dV/dR)=V*(dV/dR) and dV/dR = [itex]( \partial V/ \partial x )i +( \partial V/ \partial y )j +( \partial V/ \partial z )k [/itex] so a = V*[itex]\left[( \partial V/ \partial x )i +( \partial V/ \partial y )j +( \partial V/ \partial z )k \right] [/itex] I believe you have to use the magnitude of V, rather than dotting V into dV/dR, for some reason. I can't explain/remember why, but I think this is how it is supposed to be. Could be wrong, idk. but that's my 2 cents, hope it helps 



#4
Apr2712, 09:09 AM

P: 21

Acceleration as a function of time and position[itex]\vec{a}[/itex] = [itex]\frac{D\vec{v}}{Dt}[/itex] = [itex]\vec{v}[/itex][itex]\cdot[/itex]([itex]\vec{\nabla}[/itex][itex]\vec{v}[/itex]) + [itex]\frac{\partial \vec{v}}{\partial t}[/itex] 


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