|Apr28-12, 07:55 PM||#1|
Work required to disassemble a helium atom
1. The problem statement, all variables and given/known data
A helium atom has a rest mass of He = 4.002603u. When disassembled into its constituent particles (2 protons, 2 neutrons, 2 electrons), the well-separated individual particles have the following masses: p = 1.007276u, n= 1.008665u, e = 0.000549u.
How much work is required to completely disassemble a helium atom? (Note: 1 u of mass has a rest energy of 931.49 MeV.)
2. Relevant equations
3. The attempt at a solution
2(1.007276u + 1.008665u + 0.000549u) = 4.03298u
4.03298u - 4.002603u = .030377u
E = (0.030377u)*(931.49 MeV/u)*(3.0*10^8)^2
E = 2.5466*10^18 MeV
*I tried using c = 2.9979*10^8, however it is still wrong.
|Apr28-12, 08:08 PM||#2|
Blog Entries: 1
Did you notice that the units of (0.030377u)*(931.49 MeV/u)*(3.0*10^8)^2 are m4/s4?
The conversion 931.49 MeV/u is not a conversion between one mass and another mass, so multiplying by this and then using E=mc2 afterwards is pretty suspect
|Apr28-12, 08:13 PM||#3|
|e=mc^2, energy, helium atom|
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