- #1
LagrangeEuler
- 717
- 20
The Rushbrooke inequality: [tex]H=0, T\rightarrow T_c^-[/tex]
[tex]C_H \geq \frac{T\{(\frac{\partial M}{\partial T})_H\}^2}{\chi_T}[/tex]
[tex]\epsilon=\frac{T-T_c}{T_c}[/tex]
[tex]C_H \sim (-\epsilon)^{-\alpha'}[/tex]
[tex]\chi_T \sim (-\epsilon)^{-\gamma'}[/tex]
[tex]M \sim (-\epsilon)^{\beta}[/tex]
[tex](\frac{\partial M}{\partial T})_H \sim (-\epsilon)^{\beta-1}[/tex]
[tex](-\epsilon)^{-\alpha'} \geq \frac{(-\epsilon)^{2\beta-2}}{(-\epsilon)^{-\gamma'}}[/tex]
and we get Rushbrooke inequality
[tex]\alpha'+2\beta+\gamma' \geq 2[/tex]
My only problem here is first step
[tex]C_H \geq \frac{T\{(\frac{\partial M}{\partial T})_H\}^2}{\chi_T}[/tex]
we get this from identity
[tex]\chi_T(C_H-C_M)=T\alpha_H^2[/tex]
But I don't know how?
[tex]C_H \geq \frac{T\{(\frac{\partial M}{\partial T})_H\}^2}{\chi_T}[/tex]
[tex]\epsilon=\frac{T-T_c}{T_c}[/tex]
[tex]C_H \sim (-\epsilon)^{-\alpha'}[/tex]
[tex]\chi_T \sim (-\epsilon)^{-\gamma'}[/tex]
[tex]M \sim (-\epsilon)^{\beta}[/tex]
[tex](\frac{\partial M}{\partial T})_H \sim (-\epsilon)^{\beta-1}[/tex]
[tex](-\epsilon)^{-\alpha'} \geq \frac{(-\epsilon)^{2\beta-2}}{(-\epsilon)^{-\gamma'}}[/tex]
and we get Rushbrooke inequality
[tex]\alpha'+2\beta+\gamma' \geq 2[/tex]
My only problem here is first step
[tex]C_H \geq \frac{T\{(\frac{\partial M}{\partial T})_H\}^2}{\chi_T}[/tex]
we get this from identity
[tex]\chi_T(C_H-C_M)=T\alpha_H^2[/tex]
But I don't know how?