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What does my physics book mean? What values do these represent?

by Stradigos
Tags: book, physics, represent, values
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May4-12, 10:16 PM
P: 9
I bought physics for game programmers today to study ballistic impact, but I'm confused as to where a few numbers are coming from. I'm basically looking to understand what the values represent since the book does a bad job at telling me.

I get that Ek = .5mv.

In talking about the F-Formula, developed by Dr. L. Thompson (neither of which I can find anything about) "The equation was presented as a ratio between the plate thickness and the diameter of the projectile."

That equation: t/d = 0.0623 (((mv)^2)/((d^3)(F^2)))cos^2 angle

I realize that the above was just an example of the equation in the book, but .0623 is pissing me off. I have no idea where they get this from. Probably some number relating to steel armor since that's what he's talking about... so I'll continue...

"The coefficient F is a measure of the penetration resistance of the armor"

That equation: F = 1.8288((t/d) - 0.45)(angle^2 + 2000) + 12192.

Can someone tell me what those numbers are? I don't care where they got them from, but what are they suppose to be? I need to know so I can plug my own in...

Apparently it's also possibly to "rearrange the Thompson formula so that it is in the terms of the minimum projectile energy, Ek, necessary to penetrate the armor.

Ek = .5mv^2 = 8.025((td^2)(F^2))/(cos^2 angle)

Again... another imaginary number. What is this 8.025??? What should go there?

It says the right hand side of the last equation there tells which factors influence steel armor pen, so I'm guessing the 8.025 is relating to that, but what factor? Thickness?

To further confuse me, it seems like he then tries to take everything he's taught me so far and then simplify it.

Assuming the impact is head on and uses the second to last equation I provided to compute the F coefficient:

F = 1.8288((.01m/.009m) - .45)(2000) + 12192 = 14610

So then taking that number

.5mv^2 = 8.025 * .01 * .009^2 * 14610^2 = 1387.5 J.

It footnotes and says a 9mm bullet has a mass of .0082 kg and a muzzle velocity of 440 m/s. The bullet only does 794 J, so the armor stops the bullet.

I just need someone to tell me what those numbers represent. Much thanks!

Sorry for the lack of units, but that's literally all the book tells me. It doesn't provide units and the text doesn't indicate it. I think kg would be appropriate though.
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May5-12, 01:01 AM
Sci Advisor
P: 2,470
They kind of look like empirical formulae.

There is a relatively simple model you can use for penetration test on hard materials. It might converge to the above results if you work it out. The idea is simple. It takes a certain amount of energy to create a crack. It's the energy of the bonds that keep the material together. So the total energy required to penetrate hard armor is proportional to the area of the surface where separation occurred.

A bullet will typically punch out a cone. You can estimate the geometry of the cone by taking the ratio of the speed of sound in the material to the speed of the bullet. That will be equal to the difference of radii (base radius - bullet radius) to the thickness of material.

Finally, you need to know amount of energy per surface area required. You can estimate it from stress intensity factor or energy release rate.
May5-12, 07:49 AM
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HW Helper
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Quote Quote by Stradigos View Post
In talking about the F-Formula, developed by Dr. L. Thompson (neither of which I can find anything about) "The equation was presented as a ratio between the plate thickness and the diameter of the projectile."
Did you try Googling "Thompson F-formula impact". The first hit I got was

May6-12, 03:56 PM
P: 9
What does my physics book mean? What values do these represent?

Just wanted to post up and say that I've decided to go with a pretty generalized equation based off the Thompson F-Formula for my purposes (a game, keep in mind).

This website seemed to really explain it well:

Typically, the equation is T = (K)[(0.5)(W/g)V^2]^p

T is the thickness of the plate armor barely penetrated.

K = "catch-all" that changes with projectile nose shape, projectile size, projectile damage, definition of "penetration," plate type, and obliquity angle of impact)

W = Weight g = Gravity (Note, you don't need to do W/g since that's already figured in with kg, if you use kg).

V = Velocity

p = something I don't quiet understand, but am going to ignore for my purposes.

K was the tricky one for me. I took that list and basically started crossing off things I didn't want to factor in for the battle system. I cross off nose shape, definition of penetration (since T is enough for me) and plate type. That left me with size and damage of the projectile.

Size and damage I'm going to create my own rating called Hardness with.

In my other thread about combat design, I figured that a sword with a mass of .997 and velocity of 3.333 m/s does about 5.537 Joules of damage (yes, I'm going to call joules damage for the sake of the battle engine unless I can come up with something better).

If I want my armor to withstand that just up to the point of being penetrating, then my armor rating has to be = Projectile Joules I want to protect against * Toughness. Toughness will basically be the durability, and is the amount of beating the armor can take before breaking. I think I'm going to keep it a 0 to 1 range.

Let's say the armor has taken a couple hits but hasn't been penetrated and the toughness is now at 60%.

Against the incoming sword, 5.537 * .6 = 3.222

5.537 > 3.222, so 2.214 damage goes through and the armor rating is reduced .6/2.214 = .27 points.

This isn't official yet, but that's what I'm thinking of, as sloppy as it is.

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