|May9-12, 02:34 AM||#1|
Projectile Motion of Basketball Shot to Ring
1. The problem statement, all variables and given/known data
A basketball is thrown from a height of 2.8m above the ground and goes through a basketball ring that is 3.3m above the ground. If the release velocity was 5.5 m/s at an angle of 54 degrees upwards from the horizontal, calculate the horizontal displacement the ball will travel between being released and reaching the ring
2. Relevant equations
I know I have to find initial vertical and horizontal velocity and time
3. The attempt at a solution
I have found initial vertical velocity of 4.45m/s and horizontal velocity to be 3.23m/s
I dont know where to start with time as i have only ever done projectiles that take-off and land at the same height ?
|May9-12, 02:47 AM||#2|
For any vertical or horizontal displacement, the time taken are equal.
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