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Longitude conversion according to your latitude

by michael atlas
Tags: longitude formula
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michael atlas
#1
May15-12, 03:50 PM
P: 8
I have two latitude/longitude points. They are really close together. What I want to do is find the difference between the two longitides and calculate how many yards that would be. If I did the calculation with with the two latitudes, it would be just 2025yds per minute of latitude. However, for the longitude; being that the closer you get to the poles, the closer the lines of longitude move together, you have to apply a conversion to it.

If my lat/longs were 34.34W, 79.1N and 34.23W, 80.3N Respectively, I want to find the exact amount of yards between my two lines of longitude.

If any one had the formula to find out how many yds per minute of longitude according to what latitude I am at, I would greatly appreciate it.

Thanks,
Mike
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Studiot
#2
May15-12, 05:50 PM
P: 5,462
Can you not use the second formula I gave you in the other thread?

The radius of any circle of latitude (rθ) is given by the mean radius (r) of the earth times the cosine of the angle of latitude (θ)

rθ = rcosθ

And by the way what is your application here and there ?
michael atlas
#3
May16-12, 07:02 AM
P: 8
My application is for sonar work, programming in matlab.

When I get the answer from the other thread... I just multiply that latitude by 2025yds per degree of latitude AND longitide?

Is that true, because of the fact that I have to convert longitude given the latitude for Theta E

billiards
#4
May16-12, 08:06 AM
P: 749
Longitude conversion according to your latitude

Quote Quote by michael atlas View Post

If my lat/longs were 34.34W, 79.1N and 34.23W, 80.3N Respectively, I want to find the exact amount of yards between my two lines of longitude.

At what latitude? 79.1N or 80.3N or somewhere in the middle?

This can all be solved quite easily if you have a good grasp of spherical co-ordinates.
Studiot
#5
May16-12, 08:11 AM
P: 5,462
The difference in longitude is the distance along a parallel of latitude.

Each parallel of latitude is a circle of radius rθ = r cos(θ)

So the circumference of that parallel is 2∏rθ in yards or metres or whatever and 360 degrees in angle.

So for instance the difference between 10 west and and 20 west is 10

So this in yards is

10/360 times circumference = (10/360) * 2∏rθ where r is the mean radius in yards.

Now the latiture you use for θ is different for each point so you should take the average latitude by adding up the two latitudes and dividing by 2.

Does this make sense?
michael atlas
#6
May16-12, 02:32 PM
P: 8
Yes it does.

Appreciate it.


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