
#1
May2212, 02:24 AM

P: 144

Hi folks,
1. The problem statement, all variables and given/known data At Roanoke College it is known that 1/3 of the students live off campus. It is also known that 5/9 of the students are from within the state of Virginia and that 3/4 of the students are from out of state or live on campus. What is the probability that a student selected at random from Roanoke College is from out of state and lives on campus? 2. Relevant equations  3. The attempt at a solution It should yield: P(out off state OR lives on campus) = P(out off state) + P(lives on campus)  P(out off state AND lives on campus) thus P(out off state AND lives on campus) = P(out off state)+P(lives on campus)P(out off state OR lives on campus) =(15/9)+(11/3)(3/4) =4/9 + 2/3  3/4 =13/36 Is this correct? derivator 



#2
May2212, 03:18 AM

P: 280

Yes.




#3
May2312, 04:25 AM

P: 144

thanks




#4
May2312, 06:49 AM

Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 38,898

Probability Involving AND and OR
The phrase should be "out of state", not "out off state".



Register to reply 
Related Discussions  
a simple probability problem involving the law of total probability  Calculus & Beyond Homework  1  
probability (involving conditioning)  Calculus & Beyond Homework  1  
Probability involving a deck of cards  Precalculus Mathematics Homework  1  
Probability involving coin flips  Calculus & Beyond Homework  4  
Probability involving combinations  Precalculus Mathematics Homework  2 