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Probability Involving AND and OR |
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| May22-12, 02:24 AM | #1 |
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Probability Involving AND and OR
Hi folks,
1. The problem statement, all variables and given/known data At Roanoke College it is known that 1/3 of the students live off campus. It is also known that 5/9 of the students are from within the state of Virginia and that 3/4 of the students are from out of state or live on campus. What is the probability that a student selected at random from Roanoke College is from out of state and lives on campus? 2. Relevant equations - 3. The attempt at a solution It should yield: P(out off state OR lives on campus) = P(out off state) + P(lives on campus) - P(out off state AND lives on campus) thus P(out off state AND lives on campus) = P(out off state)+P(lives on campus)-P(out off state OR lives on campus) =(1-5/9)+(1-1/3)-(3/4) =4/9 + 2/3 - 3/4 =13/36 Is this correct? -derivator |
| May22-12, 03:18 AM | #2 |
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Yes.
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| May23-12, 04:25 AM | #3 |
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thanks
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| May23-12, 06:49 AM | #4 |
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Probability Involving AND and OR
The phrase should be "out of state", not "out off state".
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