|Jun2-12, 06:58 PM||#1|
Can someone tell me if this makes sense? (Equalities question)
I think what I just said is that if x is greater than y and y is greater than x, they must be greater than eachother by zero, thus proving they are equal. It also works if x is greater than y by z and y is greater than x by say q (though in the end both q and z are zero).
Does this make any sense?
|Jun2-12, 07:22 PM||#2|
Your conclusion is valid if you use the symbol '[itex]\leq[/itex]' which means "less than or equal to." In that case x [itex]\leq[/itex] y and y [itex]\leq[/itex] x do indeed imply that x = y. However I'm a little confused by your proof. What is z, is it supposed to be a constant? You essentially have the right idea but you need to make it a little more clear.
|Jun2-12, 08:33 PM||#3|
^Thank you for the clarification! I noticed that too, but then it sort of makes the entire thing redundant doesn't it? Ah well, journey's better than the destination I guess.
^z is any real number. You know, just a variable representing the difference between x and y.
|equalities, question, serious|
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