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Transformation Vs. Physical Law |
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| Jun10-12, 07:56 AM | #239 |
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Transformation Vs. Physical LawThe muon ratios you mention are invariant and are given by the law I cited at the beginning of the thread, without using any transform. So your question seems to have been resolved more than a hundred posts ago. |
| Jun10-12, 08:55 AM | #240 |
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| Jun10-12, 08:59 AM | #241 |
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![]() And concerning the time tau, I thought that I gave that but if not, here it is for universal as given in 1905: "the time marked by the [moving] clock (viewed in the stationary system) is slow [on the reference clock] by 1-√(1-v2/c2) seconds per second, or—neglecting magnitudes of fourth and higher order—by 1/2 v2/c2." This effect must be valid in general: not only mechanical clocks slow down by a factor γ but any natural process, including the half-life of radioactive "clocks" such as muons. Note also that the expression "viewed in the stationary system" is the reference for "laws of physics"; it's not a transformation equation, and universal can use that law for arriving muons with the earth as "stationary system". |
| Jun10-12, 09:37 AM | #242 |
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Using a transform simply converts that half-life to a different coordinate system. |
| Jun10-12, 11:45 AM | #243 |
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| Jun10-12, 12:52 PM | #244 |
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| Jun10-12, 01:07 PM | #245 |
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If you choose to call a correct derivation "just juggling mathematics" then so be it. It is still a correct derivation and completely refutes your claim. |
| Jun10-12, 01:39 PM | #246 |
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| Jun10-12, 01:45 PM | #247 |
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| Jun10-12, 11:10 PM | #248 |
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Just because we can understand a particular event by using energy conservation(Least action principle), does not mean that there is NO Force involved in the event. Whereas, you are suggesting, because we can calculate the correct results also by using spacetime metrics, it means that Time Dilation is independent of relative motion, i.e. independent of gamma factor. |
| Jun11-12, 06:57 AM | #249 |
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Your entire complaint from the OP is that physical effects like muon decay should come from physical laws and not coordinate transforms. I gave the physical law for muon decay. You then complained that simply because gamma pops out of the law that it must be a transform. In fact, you said that the "only way I know of producing gamma factor is using Transformations(Lorentz)". So I showed you that it can be produced directly from the metric without any transform. So now that you know that gamma can come from other sources than a coordinate transform it should be clear that your complaint is completely resolved. Do you now accept that the decay of muons can be explained by a law of physics that is not a coordinate transform? If not, then what possible logical reason can you have for not accepting it? |
| Jun11-12, 12:53 PM | #250 |
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[QUOTE=universal_101;3950519]
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| Jun12-12, 12:02 AM | #251 |
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But then I'm wondering where does this concept of spacetime and the metrics comes from if not from the transformations. Since there must be a physical concept behind any physical law. Why were these physical laws not discovered on their own !! And how come this physical law can be used to derive the transformations, which it could not if it were an actual physical law ! |
| Jun12-12, 12:30 AM | #252 |
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Relativity demands that we examine the laws in moving frames, and this where transformations of coordinates happen. We demand that physical laws do not change under a relabelling of spacetime points. Your remarks show a deep lack of understanding of how physics is actually done and makes me wonder why you think you are qualified to make any meaningful remarks about any aspect of physics. Your last two posts make no sense to me at all. |
| Jun12-12, 12:35 AM | #253 |
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I admit, I've not read through the entire thread, but can I give this a shot?
A muon travels on an inertial path from point [itex]A[/itex] to point [itex]B[/itex], separated by some proper time [itex]\tau[/itex], at which point it decays. This trajectory is characterized by four-velocity [itex]v[/itex]. An observer with four-velocity [itex]u[/itex] will measure the elapsed time between events [itex]A[/itex] and [itex]B[/itex] as [itex]\tau v \cdot (-u)[/itex]. If it happens that the observer has the same four-velocity as the muon, then this reduces to [itex]\tau[/itex] (in [itex]c=1[/itex] units), but any arbitrary observer will come up with a different result. There is no transformation of coordinate systems going on here. There is only each observer taking the dot product of their own four-velocity vector and the four-velocity of the muon to find one component of the muon's four-velocity in a particular basis. That, in itself, makes a physical statement about the universe: that we are free to choose any basis we wish because any direction is equivalent to any other. We choose Minkowski spacetime to model the universe because it shares that property of isotropy with what we observe in the real world. |
| Jun12-12, 01:32 AM | #254 |
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| Jun12-12, 06:00 AM | #255 |
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I noticed that in your response you carefully avoided answering the questions:
Do you now accept that the decay of muons can be explained by a law of physics that is not a coordinate transform? If not, then what possible logical reason can you have for not accepting it? The law that governs the decay of muons (in motion or at rest) is the one I provided >240 posts ago. |
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