## Heat transfer, single and double paned window. Stove and pot.

A glass window 1m x 2m and .005m thick has thermal conductivity of 1.4W/m K. Inner surface temp of 15C and outside of -20C, what is the heat loss through the glass.

double paned construction two panes separated by .01m, if glass surfaces are 10C and -15C, with air thermal conductivity of .024W/m K

q''= -k dT/L

q’’= 1.4W/m•K((288K-253K)/(.005m)), q’’=9800W/m2, q=9800W/m2 • 2m2 = 19600W

Double Paned: Rtot = L/kg+L/ka+L/kg,
Rtot = (.005m)/(1.4W/(m•K))+(.010m)/(.024W/(m•K))+(.005m)/(1.4W/m•K)
Rtot=0.424K/W,
q=ΔT/Rtot, q=(283K-253K)/(.0424K/W), q=70.75W

It just seemed like too big of a difference to be the correct answer. Just one more I wasn't sure of.

The 5mm thick bottom of a 200mm diameter pan may be copper(k = 390W/m K) or aluminum (240W/m K). When used to boil water the surface of the bottom exposed to the water is nominally 110C. IF the heat transferred from the stove to the pot is 600W, what is the temperature of the surface in contact with the stove for the two materials

A=0.031416m2, q''=19100W
q=k(Tbottom-Tin)/L (q•L)/k+Tin=Tbottom,alum
Tbottom,alum=(19100W/m^2(.005m))/(240W/m•K)+383K = 383.398K
Tbottom,copper=(19100W/m^2(.005m))/(390W/m•K)+383K = 383.245K

Again, just wasn't sure, it seemed the numbers were too close.

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 q=ΔT/Rtot, q=(283K-253K)/(.0424K/W), q=70.75W You have a slight error in the above. It should be 82.6. The .0424 should be .424. The huge difference comes from the additional resistance of the air. Look at the ratios of k/dx for air gap and for a pane of glass. The difference is large. In a real life problem, you also have the radiation factor where the hotter pane loses heat to the cooler pane. It has an effect but is not considered in this problem. To complicate the issue further, there is motion of the trapped gas between the panes that further enhances the heat transfer.
 Second part dealing with the pot on the stove is correct.

## Heat transfer, single and double paned window. Stove and pot.

Thank you, just wanted to make sure I had the right idea for the problem.