# A train of 3000 KN weight starts from rest and reached a velocity of 54 km/h after o

by manal950
Tags: 3000, km or h, reached, rest, starts, train, velocity, weight
 P: 177 Hi all 1 ) A train of 3000 KN weight starts from rest and reached a velocity of 54 km/h after one min . if the frictional resistance of the track is 5N/KN of the train's weight . Find the tractive force developed by the engine ? I don't understand what is mean "tractive force " ?? anyway I start solve the question w = 3000 kN mass = 305810 u = 0 v = 54 km/h v = u + at a = 0.25 F = m X a F = 305810 X 0.25 76452.5 N
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P: 6,202
 Quote by manal950 Hi all 1 ) A train of 3000 KN weight starts from rest and reached a velocity of 54 km/h after one min . if the frictional resistance of the track is 5N/KN of the train's weight . Find the tractive force developed by the engine ? I don't understand what is mean "tractive force " ?? anyway I start solve the question w = 3000 kN mass = 305810 u = 0 v = 54 km/h v = u + at a = 0.25 F = m X a F = 305810 X 0.25 76452.5 N
Right a = 0.25 m/s2 (Always remember to put your units).

In the formula F=ma, a is the resultant acceleration of the mass m (Train in this case). So F is the resultant force.

If you draw a free body diagram, what are the forces on the train? (The tractive force is essentially the force generated by the train itself).
 P: 177 force on the train 1 weight 2 frictional resistance 3 tractive force now How I can find the tractive force
 P: 177 A train of 3000 KN weight starts from rest and reached a velocity of 54 km/h after o I don't know where is the other helper ..
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P: 6,202
 Quote by manal950 force on the train 1 weight 2 frictional resistance 3 tractive force now How I can find the tractive force
In which direction do these forces act?

How would you find the resultant horizontal force?
 P: 177 I don't know how to find resultant horizontal force? anyway the direction for each one weight dawn , frictional resistance opposite of tractive force
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P: 6,202
 Quote by manal950 I don't know how to find resultant horizontal force? anyway the direction for each one weight dawn , frictional resistance opposite of tractive force
Right so let's say frictional force is going left and the tractive force is going right. The train is moving to the right. How would you calculate the value of the force that the train is moving with from these two forces?

in other words, if we are in a tug of war competition and you are pulling with 10 N and I am pulling with 11 N, what would be the resultant force in this case?
 P: 177 Resultant force = tractive force - frictional force
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P: 6,202
 Quote by manal950 Resultant force = tractive force - frictional force
Right!

So you calculated the resultant force in your first post. And they told you what the frictional force was. So you can rearrange to get the tractive force.
 P: 177 tractive force = Resultant force - frictional force = 76452.5 - 3000 now this is correct ??
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P: 6,202
 Quote by manal950 tractive force = Resultant force - frictional force = 76452.5 - 3000 now this is correct ??
Check the signs in your equation.
 P: 177 76452.5 + 3000 ... ?
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P: 6,202
 Quote by manal950 76452.5 + 3000 ... ?
That should work.
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P: 39,682
 Quote by manal950 tractive force = Resultant force - frictional force = 76452.5 - 3000 now this is correct ??
Remember that the "tractive force", the force applied to the track by the locomotive, must be larger then the resultant force as it has to overcome the frictional force.

You can write it as "Resultant force- frictional force" if you remember to treat "frictional force" as negative.
 P: 177 now is my answer if fully correct ... ?
 HW Helper P: 6,202 It should be.
 P: 177 my teacher said the answer is not correct and he said why you don't multiply 5 X 3000 I don't know what he mean ? and my other questions is the Resultant force ma + tractive force or only F = ma
P: 963
 Quote by manal950 my teacher said the answer is not correct and he said why you don't multiply 5 X 3000 I don't know what he mean ?
frictional resistance of the track is 5N/KN of the train's weight

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