|Jun14-12, 06:14 PM||#1|
Find an equation to the tangent line to a curve and parrallel
1. The problem statement, all variables and given/known data
Find an equation of the tangent line to the curve y = x√x that is parallel to the line
y = 1+3x.
2. Relevant equations
m = 3
3. The attempt at a solution
Here is my attempt: dy/dx(x) * dy/dx(x^(1/2)) = (1) * (1/2x^(-1/2)) = (1/2x^(-1/2))
(1/2x^(-1/2)) = 3 → x^(-1/2) = 6 → -√x = 6
x = -√36 = 6 → -6=6 -1=1
Thank you, I will not be able to respond for a bit as im leaving for home now.
|Jun14-12, 06:35 PM||#2|
|Jun15-12, 12:08 AM||#3|
To add to what LCKurtz said about your oversimplification of the product rule, what you wrote does not mean what you think.
The expression dy/dx(x) means dy/dx times x, which I'm pretty sure isn't what you intended.
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