## Find the length of the curve r = cos^2(theta/2)

Find the length of the curve r = cos^2(theta/2)

I'm hopelessly lost.
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 consider a simpler case y=x^2 and what is the length from x=0 to x=10? dlen = (dx*dx + dy*dy) ^ (1/2) based the pythagorian theorem and dy= 2xdx so dlen = ( dx*dx + 4x^2 dx*dx ) ^ (1/2) = (1 + 4x^2) dx then integrate over x to get the solution In your equation you must consider polar coordinates so that the dlen element is: dlen = ( dr^2 + (r*dtheta)^2 ) ^ (1/2) plugin for dr and r and integrate over theta to get the length
 Thanks a lot, makes more sense! Forgive my ignorance by the way.

 Tags curve, integral, integration, length, polar

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