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Tangent space as best approximation |
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| Jul4-12, 02:04 PM | #1 |
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Tangent space as best approximation
Dear all,
in what sense the tangent space is the best approximation of a manifold? The idea is clear to me when we think about a surface in Rn and its tangent plane at a point. But what does this mean when we are referring to very general manifolds? In what sense "approximation" and in what sense "best"? Thanks. Goldbeetle |
| Jul4-12, 02:12 PM | #2 |
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Hum. Well, any manifold can be embedded in R^N for N large enough, so the case where M is in R^n is the most general case in a sense.
But yeah, in the abstract setting I don't think it makes sense in any way. But maybe I'm wrong. |
| Jul4-12, 02:47 PM | #3 |
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I believe you use the definition of tangent space in terms of derivations when the manifold is stand-alone.
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| Jul4-12, 06:45 PM | #4 |
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Tangent space as best approximation
The idea of best linear approximation requires the manifold to be embedded in another manifold.
The abstract tangent space will be mapped to the best linear approximation under any embedding into Euclidean space. So the tangent space may be thought of as an abstract space whose geometric realization is always the best linear approximation. |
| Jul4-12, 07:27 PM | #5 |
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There is an equivalence between derivations and tangent vectors, in that each can be seen as being the other, i.e., every derivation can be seen as a tangent vector and viceversa. |
| Jul4-12, 07:53 PM | #6 |
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| Jul4-12, 08:12 PM | #7 |
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to have a vector space structure to talk about planes? There is a such a thing as an abstract general plane over a field ( the set of combinations f1p+f2 y for fi in the field --this is how we work in abstract projective spaces over a field) , but I don't see how to get the structure to have both planes and a norm , for , what do you mean when you say that ||v-w||<e , where v is in the tangent plane and w is in the manifold? ℝn allows this because it is a normed space. How do you do it in a generic ambient manifold X? |
| Jul4-12, 08:45 PM | #8 |
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