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Polymer Engineering question related to Von Mises yield criterion |
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| Jun12-12, 03:13 AM | #1 |
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Polymer Engineering question related to Von Mises yield criterion
It is a proof question. Does anyone can tell me how to do this question?question 22.2
it is the question for extra credit for my final exam. thank you so much. |
| Jul14-12, 01:19 AM | #2 |
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You can find A and B with two simultaneously equations.
For the first equation assume uniaxial tension yielding - i.e. take σ1 as fty and σ2=σ3=0. For the second equation assume uniaxial compression yielding. This is a polymer so it makes sense that fty and fcy would be different values - and they have to be different values otherwise you'd find that A=0. Once you have A and B, then consider the hydrostatic case - i.e. take σ1=σ2=σ3=σ. Solve for σ. |
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