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Every prime greater than 7 can be written as the sum of two primes |
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| Jul12-12, 07:36 PM | #1 |
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Every prime greater than 7 can be written as the sum of two primes
"Every prime greater than 7, P, can be written as the sum of two primes, A and B, and the subtraction of a third prime, C, in the form (A+B)-C, where A is not identical to B or C, B is not identical to C, and A, B, and C are less than P."
True? |
| Jul13-12, 02:13 AM | #2 |
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Nope. Try 11.
You can't use 2 for A,B or C because the other 2 primes would be odd and you'd get an even number, so the only primes you can use are 3, 5 and 7. The largest number you can form is 7+5-3 = 9 |
| Jul13-12, 04:32 AM | #3 |
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Of course, if the question is about numbers relatively prime to p, then (p-1)+2-1 is a solution to every prime. But he said that wasn't the case either. |
| Jul13-12, 04:55 AM | #4 |
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Every prime greater than 7 can be written as the sum of two primes
It's true for all primes between 13 and 9973.
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| Jul13-12, 05:29 AM | #5 |
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Using Goldbach's conjecture, any even integer is the sum of two primes (at least up to 1.609 × 10^18).
Meaning that (p+3) is the sum of two primes, and 3 can be subtracted to get p. Or more generally (p+q) is the sum of two primes, where q is a prime number, and q can be subtracted to get p. I'm not sure how you'd go about making proving it's possible when A is not equal to B. |
| Jul15-12, 08:27 AM | #6 |
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But if you subtract 3 from a prime, the result is not necessarily a prime.
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| Jul15-12, 08:46 AM | #7 |
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Right, ignore my posts, I've decided they're nonsense.
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