|Jul15-12, 05:32 PM||#1|
Limiting Reagents With 3 Reactants
1. The problem statement, all variables and given/known data
So my test is tomorrrow, and I have troubles with limiting reagents, I can get them right sometimes with the 2 reactant questions, but not always with 3.... so the question is
Q: What mass of phosphorus (P4) is produced when 41.5g of calcium phosphate, 26.5g of silicon diioxide, and 7.80g of carbon are reacted according to the eqation:
2Ca3(PO4)2 + 6SiO2 + 10C -> P4 + 6CaSiO3 + 10CO
2. Relevant equations
3. The attempt at a solution
I've checked that the equation is balanced
and I calculated the moles of 2Ca3(PO4)2 which is 0.1337 mols, 0.441 mols for 6SiO2 and 0.0649 mols for 10C.
after this idk what ratios to use to calculate what....
|Jul17-12, 02:56 PM||#2|
No matter how many reactants, the correct answer is always the one giving the lowest amount of products.
|Jul18-12, 04:27 PM||#3|
Then, write the ratio of theoretical moles to actual moles for each compound. Finally, for each ratio, divide the whole ratio by its denominator so all the ratios have a denominator of 1. Then see which is the lowest.
Assuming you have all the grams to moles converted properly, you get this:
Since 0.00649 is the least for 1 mol, then Carbon is the limiting reagent.
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