## Writing Volume as a Function of Height for an Open Box

1. The problem statement, all variables and given/known data

An open box of maximum volume is to be made from a square piece of material 24 centimeters on a side (24-2x) by cutting equal squares from the corners and turning up the sides. The table shows the volumes V (in cubic centimeters) of the box for various heights, x (in centimeters).

(x, V): (1,484), (2,800), (3,972), (4,1024), (5,980), (6,864)

If V is a function of x, write the function and determine its domain.

3. The attempt at a solution

I'm completely stuck on this. I tried recreating the table values by using the volume of a cube formula, but that didn't work. If anyone could give me a nudge in the right direction that would be helpful, thanks.

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Mentor
 Quote by M83 1. The problem statement, all variables and given/known data An open box of maximum volume is to be made from a square piece of material 24 centimeters on a side (24-2x) by cutting equal squares from the corners and turning up the sides. The table shows the volumes V (in cubic centimeters) of the box for various heights, x (in centimeters). (x, V): (1,484), (2,800), (3,972), (4,1024), (5,980), (6,864) If V is a function of x, write the function and determine its domain. 3. The attempt at a solution I'm completely stuck on this. I tried recreating the table values by using the volume of a cube formula, but that didn't work. If anyone could give me a nudge in the right direction that would be helpful, thanks.
What cubic function do you get for the volume of the box ?

 Recognitions: Gold Member Science Advisor Staff Emeritus The problem tells you that the base is a square that has side length 24- 2x. What is the area of the base? How do you go from "area of base" to "volume"?

## Writing Volume as a Function of Height for an Open Box

 Quote by HallsofIvy The problem tells you that the base is a square that has side length 24- 2x. What is the area of the base?
For a square the area would be the square of the side length.

A= (24-2x)(24-2x)
= 576-48x-48x+4x²
= 4x²-96x+576

 Quote by HallsofIvy How do you go from "area of base" to "volume"?
Would you cube the side length?

Recognitions:
Homework Help
 Quote by M83 For a square the area would be the square of the side length. A= (24-2x)(24-2x) = 576-48x-48x+4x² = 4x²-96x+576 Would you cube the side length?
Why on Earth would you do that? If I have a box whose base has area 10 m2 and whose height (= sides) are 2 m, what is the volume (in units of m3)?

RGV

Recognitions:
Homework Help
 Quote by M83 I'm completely stuck on this. I tried recreating the table values by using the volume of a cube formula, but that didn't work.
That's because you don't have a cube to begin with, you have a rectangular prism ("box"). You do know that the volume of a rectangular prism is $V = lwh$ (l = length, w = width, h = height), right?

 Tags functions, volume