Clarification regarding rolling cylinder with CG slightly above

seshikanth

Hi

Can any one please clarify the following?

Let there by a rolling cylinder on an inclined plane. Let the solid cylinder(with Center O) on the inclined plane has Center of gravity at a distance 'c' slightly above O. If the cylinder is displaced slightly through an angle θ then

[Let N = normal reaction; F= Rolling friction]

1. What is the work done by rolling friction F
I think, W1 = F. c Sinθ. ---- Can you tell am i correct here?

2. What is the work done by Normal Reaction?
I think it is W2 = R. (c - c Cosθ) ; --- Can you tell me if i am correct here? I know that the work done by normal reaction for a cylinder with center O as zero !



Thanks,

seshikanth

Can any one have a look at this?

Thanks,

seshikanth

gentle reminder