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Why can't Light Escape Black Holes? |
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| Aug3-12, 11:29 AM | #1 |
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Why can't Light Escape Black Holes?
If light is transmitted by photons and photons are massless and gravity only affects particles with mass, then why can't light escape black holes' giant gravitational force?
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| Aug3-12, 11:32 AM | #2 |
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Gravity doesn't only affect particles with mass. In general relativity, the stress-energy tensor is the source of gravitation. Since photons have energy, they also gravitate.
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| Aug3-12, 11:46 AM | #3 |
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I swear a read that massless particles weren't affected by gravity but it must've just been that they don't create their own gravitational fields. Ether way that clears that up thanks
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| Aug3-12, 11:51 AM | #4 |
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Why can't Light Escape Black Holes? |
| Aug3-12, 12:04 PM | #5 |
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But doesn't the mass of an object affect how much it warps spacetime? so how could photons curve spacetime, or is it based on their energy?
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| Aug3-12, 12:22 PM | #6 |
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| Aug3-12, 03:45 PM | #7 |
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A succinct description was given in another discussion: One especially interesting example of gravity is the negative pressure attributed to dark energy: such negative pressure is repulsive!! It is believed to be the cause of cosmological expansion. An observational example of gravity bending light is 'gravitational lensing'...and was a major factor in confirming Einstein's prediction....Wikipedia discusses it. |
| Aug3-12, 04:15 PM | #8 |
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Thanks Naty. I should've been a bit mire careful with my terminology, and used momentum instead of KE. And thanks for the quote.
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| Aug3-12, 07:52 PM | #9 |
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Isn't it because massive gravitation deforms spacetime so much that with respect to an outside observer, time has almost stopped within a black hole? Since light's speed is constant per unit of time, that means its progress toward the outside world would be almost infinitely slow.
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| Aug3-12, 09:35 PM | #10 |
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The much better way to put it is that black holes bend space so much that within the event horizon, every possible path is pointed inwards. The analogy is that it is a hill so steep that you cannot possible walk up it, no matter how strong you are, you must walk down. |
| Aug3-12, 11:53 PM | #11 |
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First of all there is a difference between the rest mass and the relativistic MASS, in general relativity an object which moves with a velocity shall experience an in crease in its mass. Similarly the rest mass of a photon is zero but yet its energy provides its mass (m=hf/c2).The second thing is that , its more important to know how gravity actually works, gravity is nothing but curves and disturbances caused by the gravitational field with the space time, also see gravitational lensing, it will justify Ur questions .
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| Aug3-12, 11:55 PM | #12 |
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i wonder what happens to a photon once it comes to rest and its rest mass becomes zero, such that no gravity can act on it, so should the photon have escaped , just after it was sucked?
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| Aug3-12, 11:59 PM | #13 |
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| Aug4-12, 02:36 AM | #14 |
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| Aug4-12, 03:38 AM | #15 |
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Time always goes on 'as usual' from any standpoint. It's just that you might see someone else's time differ from yours. Likewise, light always travels at the same speed c.
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| Aug4-12, 06:49 AM | #16 |
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Here are a few more relevant comments I saved: And good separate discussion is here for those interested: Does the speed of moving object curve spacetime? http://www.physicsforums.com/showthread.php?t=602644 |
| Aug6-12, 08:53 AM | #17 |
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descriptions there is no such effect. Even with Schwarzschild coordinates which are usually used for non rotating non charged black holes, a hovering [stationary] observer [either near the horizon or millions of miles distant] detects such a timelike horizon while a free falling observer does not detect any horizon whatsoever. The former gets fried by radiation, the latter sees none; this is entirely analogous to the Unruh effect. |
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| black, gravity, hole, light, photon |
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