|Nov7-12, 04:41 AM||#1|
Derivative of [s=ut+.5at^2]
I'm currently in year 11 (Australia) and my physics class has recently started projectile motion. I noticed in class that the elementary differential calculus I've been learning in math could be applied to the questions we are working on. I'd been itching to try it out and today, after school, I did a question and (naturally) was able to solve it using what I had learned.
In the particular question I solved, it was necessary to find the derivative of the formula:
f(t) = ut + .5at2 , where f(t) = SHorizontal
f'(t) = u + at
v = u + at
Thanks for any help.
|Nov7-12, 09:13 AM||#2|
Velocity is defined as the rate of change of position with respect to time.
If you were to plot position as a function of time, velocity would be the slope of the position-time curve. Similarly, acceleration is the rate of change of velocity with respect to time. If you plotted velocity as a function of time, acceleration would be the slope of the velocity-time curve.
|Nov7-12, 04:42 PM||#3|
I realized before I fell asleep that the slope of the tangent at any point along that function with t on the x-axis is the velocity at that point in time (obviously).
Thanks for the help.
|2d motion, classical physics, derivative, projectile motion, vector motion|
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