Register to reply

Requirements for fission

by mitch_1211
Tags: fission, requirements
Share this thread:
mitch_1211
#1
Nov11-12, 09:31 PM
P: 99
So I think, as a rule of thumb that for fission to be possible [itex]\frac{Z^2}{A}[/itex][itex]\geq[/itex]47

I want to be able to derive this relationship though..

If a nucleus deforms into an ellipsoid, its surface area can be described by

4[itex]\pi[/itex]R2(1+[itex]\frac{2}{5}[/itex][itex]\epsilon^2[/itex] + ...) call this X

And its Coulomb energy can be described as

[itex]\frac{3Z^2}{20\pi\epsilon_0R}[/itex](1-[itex]\frac{1}{5}[/itex][itex]\epsilon^2[/itex] + ...) call this Y

And so ΔBE = X-Y

For fission to occur set ΔBE ≤ 0

Once I've done all this I'm not sure how to get ΔBE in terms of A and Z only. I know R = r0A1/3

thanks
Phys.Org News Partner Physics news on Phys.org
Symphony of nanoplasmonic and optical resonators produces laser-like light emission
Do we live in a 2-D hologram? New Fermilab experiment will test the nature of the universe
Duality principle is 'safe and sound': Researchers clear up apparent violation of wave-particle duality
mitch_1211
#2
Nov11-12, 09:35 PM
P: 99
I should mention that [itex]\epsilon[/itex] is an arbitrary deformation parameter associated with the ellipsoid and can be factored out
mfb
#3
Nov12-12, 07:40 AM
Mentor
P: 11,869
You can use that formula for R and solve for ##\frac{\partial (X-Y)}{\partial \epsilon}=0##.
I would expect that this overestimates the required Z^2/A - if that derivative is negative, the nucleus should not form at all or decay within less than a femtosecond.


Register to reply

Related Discussions
Q Value for spontaneous fission and neutron induced fission Introductory Physics Homework 1
Fission yield of fission products Nuclear Engineering 10
Reactor Fission VS. Weapon Fission General Physics 10
Programming for Physicist or a Astronomer Academic Guidance 1
Earth and Planetary Sciences requirements Academic Guidance 1