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Perturbation Theory (Non-Degenerate) |
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| Nov23-12, 08:21 AM | #1 |
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Perturbation Theory (Non-Degenerate)
If I have V(x)=[itex]\frac{1}{2}[/itex]m[itex]\omega^{2}[/itex]x[itex]^{2}[/itex] (1+ [itex]\frac{x^{2}}{L^{2}}[/itex])
How do I start to solve for the hamiltonian Ho, the ground state wave function ?? Calculate for the energy of the quantum ground state using first order perturbation theory? |
| Nov25-12, 05:34 AM | #2 |
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[itex]H= H_{0} + H_{p} [/itex]
So basically, you have an aditional term, [itex]H_{p} = \frac{1}{2L^{2}}mω^2 x^4 [/itex], that perturbates your hamiltonian. You already know the solution for the harmonic oscillator, [itex]H= H_{0} = \hbarω(n + \frac{1}{2}) [/itex], so you just have to find the corrections for the [itex] H_{p} [/itex]. hope i made myself clear ( ; |
| Nov26-12, 12:35 AM | #3 |
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so does this mean my hamiltonian would be [itex]H= \hbarω(n + \frac{1}{2}) + \frac{1}{2L^{2}}mω^2 x^4 [/itex] ?
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| Nov26-12, 06:58 AM | #4 |
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Perturbation Theory (Non-Degenerate)
Don't you know the ground state wave function of unperturbed oscillator.you can see them elsewhere and then just evaluate(with normalized eigenfunctions)
<E>=∫ψ0*(Hp)ψ0 |
| Nov26-12, 07:02 AM | #5 |
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I actually dont know the wave function.. That's also my prob... if i only know the wave function I'll be able to solve this.
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| Nov26-12, 07:09 AM | #6 |
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| Nov26-12, 07:11 AM | #7 |
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Is this the same for an anharmonic oscillator? That is the problem about.
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| Nov26-12, 07:18 AM | #8 |
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No,you use unpertubed harmonic oscillator wave function for calculation.
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