# Newton Raphson Method on Fortran90

by jhosamelly
Tags: fortran90, method, newton, raphson
 P: 126 Here's what I need to do: "Compare the effectiveness of the bisection method and Newton’s method for the equation x^3−2x−2 = 0 which has a single root between x=−4 and x = 2." So far I've done ok. this is working but of course I need to do iteration which I don't know how. Can someone teach me please? I'm trying the Newton-Raphson Method first. Thanks for the help in advance. EDITED: Sorry, I posted the wrong pic earlier. Here's the correct one.
 P: 838 program nr real:: x, xnew, err write(*,*) "starting x?:" read(*,*) x do xnew = x - ( (x**3 - (2*x) - 2) / ( ( 3*(x**2) )-2) ) err = 100*abs( (xnew-x)/x ) x = xnew write(*,*) "x = ", xnew, " error = ", err if (err < 0.000001) exit end do end program nr
 P: 126 thanks :))) Is that the iteration already?
P: 838

## Newton Raphson Method on Fortran90

Yes.

Isn't it? Run it and verify the solution

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