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Newton Raphson Method on Fortran90 |
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| Dec2-12, 01:00 AM | #1 |
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Newton Raphson Method on Fortran90
Here's what I need to do:
"Compare the effectiveness of the bisection method and Newton’s method for the equation x^3−2x−2 = 0 which has a single root between x=−4 and x = 2." So far I've done ![]() ok. this is working but of course I need to do iteration which I don't know how. Can someone teach me please? I'm trying the Newton-Raphson Method first. Thanks for the help in advance. EDITED: Sorry, I posted the wrong pic earlier. Here's the correct one. |
| Dec2-12, 12:34 PM | #2 |
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Code:
program nr
real:: x, xnew, err
write(*,*) "starting x?:"
read(*,*) x
do
xnew = x - ( (x**3 - (2*x) - 2) / ( ( 3*(x**2) )-2) )
err = 100*abs( (xnew-x)/x )
x = xnew
write(*,*) "x = ", xnew, " error = ", err
if (err < 0.000001) exit
end do
end program nr
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| Dec3-12, 12:49 PM | #4 |
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Newton Raphson Method on Fortran90
Yes.
Isn't it? Run it and verify the solution |
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