
#1
Dec412, 04:57 PM

P: 8

1. The problem statement, all variables and given/known data
http://tinypic.com/r/e8v1ad/6 ^^ that is a photo of the circuit 2. Relevant equations P = I*V , but i dont understand how to do it with two loops and two batteries like in this photo. 3. The attempt at a solution I have calculated I1 to be .9, I 2 to be .15 and I3 to be .75. On the very left of the photo is a 15 V battery and the resistor on the bottom that you cant really read is 100 olms. The other battery (i put a square around the batterys) is 9 V. Just kinda confused on how to put them together. thnks for your help 



#2
Dec412, 06:47 PM

Mentor
P: 11,419

What method did you you use to find the currents? Can you show more of your work?
(I ask because they don't look right to me). From what I can tell from your attached picture the circuit looks something like this: 



#3
Dec512, 01:23 AM

P: 82

Some suggestion: You allready suggested that there is 2 loops. Define the total potential energy of each loop in terms of the formula V = I*R... So if you choose the first loop, try defining it in terms of the equation. Do the same for the second loop and then you need a third equation seeing that you have 3 variables. How can you define these variables in terms of each other? Not an expert on electrical things but this seems like first principals...




#4
Dec512, 01:25 AM

P: 82

Compute the total power delivered to the circuit by two batteries
Also when setting your equations, remember that flow goes from positive to negative for your loops, not as you stated in your second loop...




#5
Dec512, 07:51 AM

Mentor
P: 11,419





#6
Dec512, 08:22 AM

P: 82

But thanks for also correcting me, learned something myself... 


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