# Energy-Time Uncertainty Relation

by harjyot
Tags: energytime, relation, uncertainty
 P: 42 I was trying to Go from the uncertainty principle to its energy-time counter part. i know the maths is a bit off,but the idea is correct? dx=position p=momentum e=energy $\upsilon$=frequency $\lambda$=wavelength c=velocity of electromagnetic radiations dt=time now , $\lambda$=h/p.............(i) c=$\upsilon$.$\lambda$.............(ii) e=h.$\upsilon$ e=(h.c)/$\lambda$ replacing $\lambda$'s value here from (i) e=(h.c)/(h/p) e=c.p now c = velocity of light , it can be written as dx/dt e= (dx/dt).p multiplying by dt on both sides e.dt=(dx/dt).dt.p e.dt=dx.p Therefore frome this relation if we straight away incorporate this in place of the σx.σp≥h/4π cannot we get σe.σt≥4π
 Quote by harjyot I was trying to Go from the uncertainty principle to its energy-time counter part. i know the maths is a bit off,but the idea is correct? dx=position p=momentum e=energy $\upsilon$=frequency $\lambda$=wavelength c=velocity of electromagnetic radiations dt=time now , $\lambda$=h/p.............(i) c=$\upsilon$.$\lambda$.............(ii) e=h.$\upsilon$ e=(h.c)/$\lambda$ replacing $\lambda$'s value here from (i) e=(h.c)/(h/p) e=c.p now c = velocity of light , it can be written as dx/dt e= (dx/dt).p multiplying by dt on both sides e.dt=(dx/dt).dt.p e.dt=dx.p Therefore frome this relation if we straight away incorporate this in place of the σx.σp≥h/4π cannot we get σe.σt≥4π