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On the nature of the "infinite" fall toward the EH |
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| Dec5-12, 04:08 PM | #52 |
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On the nature of the "infinite" fall toward the EHSuppose that, in addition to Alice and Bob, we have Charlie, who is hovering at a constant altitude close to, but above, the horizon. Charlie's "rate of flow of time" is slower than Bob's. How do we know? Because we can compute Charlie's proper time along his worldline, and verify that it "ticks" at exactly the same rate as his instruments, physiological and cognitive processes, etc. The *same* reasoning, and the *same* kind of computation, tells us that Alice experiences a finite amount of time to the horizon. Her instruments record a finite amount of time; her physiological and cognitive processes progress by a finite amount of time; etc. So if the reasoning applies to Charlie, it should apply to Alice as well. |
| Dec5-12, 04:08 PM | #53 |
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I've come up with a somewhat simpler approach for presenting the solution for the EF geodesic equations.
Let r, v be the Eddington-Finklesein (EF) coordinates, which are presumed to be functions of proper time [itex]\lambda[/itex]. Then let: [tex]\dot{r} = \frac{dr}{d\lambda} \hspace{3cm} \dot{v} = \frac{dv}{d\lambda}[/tex] The Ingoing Eddington Finklestein metric (gemoetrized) is http://en.wikipedia.org/w/index.php?...ldid=516198830 [tex]-(1-2m/r) dv^2 + 2\,dv\,dr [/tex] The Christoffel symbols are: [tex]\Gamma^{v}{}_{vv} = \frac{m}{r^2}[/tex] [tex]\Gamma^{r}{}_{vv} = \frac{m(1-2m/r)}{r^2}[/tex] [tex]\Gamma^{r}{}_{vr} = \Gamma^{r}{}_{rv} = -\frac{m}{r^2}[/tex] So we can write the geodesic equations as [tex] \ddot{v} + \Gamma^{v}{}_{vv} \dot{v}^2 = \frac{d \dot{v}}{dr} \dot{r} + \frac{m}{r^2} \dot{v}^2 = 0 [/tex] [tex] \ddot{r} + \Gamma^{r}{}_{vv} \dot{v}^2 + 2 \,\Gamma^{r}{}_{vr} \dot{v} \dot{r} = \frac{d \dot{r}}{dr} \dot{r} + (1-2m/r)\frac{m}{r^2} \dot{v}^2 - 2 \frac{m}{r^2} \dot{r}\dot{v} = 0 [/tex] Note that I've used the chain rule to write [tex]\ddot{v} = \frac{d^2 v}{d \lambda^2} = \frac{d \dot{v}}{d \lambda} = \frac{d \dot{v}}{dr}\frac{dr}{d\lambda} = \frac{d \dot{v}}{dr} \dot{r} [/tex] Then we can write the solution in infalling EF coordinates for m=2 as: [tex]\dot{r} = - \sqrt{\frac{4}{r}}[/tex] [tex]\dot{v} = \frac{\sqrt{r}}{2+\sqrt{r}} [/tex] And just plug them into the geodesic equations above to demonstrate that they are a solution. Note that [itex]\dot{r}[/itex] is negative, the first post had a sign error for the equivalent expression. The math here is only mildly obnoxious compared to the previous expressions, though I've skipped over a lot of textbook stuff like computing the EF metric (the Wiki does that), and computing the Christoffel symbols for said metric. [add]If you want r as a function of [itex]\lambda[/itex], it remains [tex]r = \left(9 \lambda^2\right)^{\frac{1}{3}}[/tex] |
| Dec5-12, 04:08 PM | #54 |
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| Dec5-12, 04:14 PM | #55 |
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| Dec5-12, 04:20 PM | #56 |
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A better way to say it might be: "for all events covered by both charts, all invariants at those events come out the same when computed in both charts". |
| Dec5-12, 04:51 PM | #57 |
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1) We must add a couple of new axioms the theory: Universes containing naked singularities are prohibited (as a corollary, closed universes are prohibited because event horizons cannot technically be defined for them; the required new law I give next cannot be stated for a closed universe). Eternal WH-BH are prohibited. (Much stronger than 'we think not physically plausible'). 2) We supplement the EFE with a new universal boundary law: The universe is bounded (chopped in spacetime) such that the world line of any particle or fluid element always has null paths extending from it to null infinity. Don't you find it contrived to muck up a beautiful, elegant theory with such additions? [Edit: An example of how strange this modified theory is shown by examining the history of a late infaller for an O-S type collapse. It is a requirement of this theory that some matter disappear from existence at a certain finite local time. Freezing won't work. The reason is that a late infaller following the collapse has their world line chopped at the horizon, and this late infaller has encountered no matter on the way. There is no possible way to avoid this while keeping the EFE in any form. This means that all the orginal collapsing matter vanished, not just froze. To avoid this, we need to modify the EFE itself such that matter world lines in the collapsing body follow different spacetime trajectories than the EFE predicts, such that the dust boundary exists outside the EH when the later infaller encounters it (at the horizon). This new prediction cannot be accommodated without significant change to the EFE itself.] |
| Dec5-12, 04:59 PM | #58 |
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![]() If Alice's local "rate of t" were reduced to zero then then Alice would never know it; she would simply freeze and be oblivious to it for eternity. To be clear, I'm not saying this is what happens at the EH according to GR, I'm just pointing out that the usual refutation against the distant observer proclaiming that Alice freezes is that time does not slow down locally in her frame according to her experience; this on its own is not a valid refutation. |
| Dec5-12, 05:07 PM | #59 |
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I think the weaker formulation is both more practical and more widely accepted. Consider, for example, the way that two-dimensional hyperbolic coordinates allow me to make predictions only in one quadrant of a plane, whereas Cartesian coordinates work for the entire plane. No one would seriously argue that the broader Cartesian coordinates are illegitimate because they make predictions where hyperbolic coordinates don't. But this is basically the situation that we have when we write the Schwarzchild solution for the vacuum around a spherically symmetric non-rotationg massive body in either Schwarzchild coordinates or (for example) KS coordinates. We never get disagreeing predictions, but we do find regions of spacetime where the KS coordinates make predictions and the SC coordinates do not. Some of these predictions (both in and out of the region of overlap) may strike us as non-physical, but that's not a problem with the coordinates. |
| Dec5-12, 05:12 PM | #60 |
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| Dec5-12, 05:22 PM | #61 |
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One can certainly say that Alice appears to freeze according to the coordinate time "t". But is this physically significant? It might be instructive to consider Zeno's paradox. I'll use the wiki definition of the paradox. At a zeno time of 1, Achilles is 50 meters behind the tortise. At a zeno time of 2, Achillies is 25 meters behind the tortise At a zeno time of n, Achillies is 100/(2^n) meters behind the tortise. Then, as n goes to infinity, Achillies is always behind the tortise. So, in "zeno time", Achilles never does catch up with the tortise, even as "zeno time" appoaches infinity. Are we therefore justified in claiming that Zeno was right, and that Achilles never catches the tortise? I don't think so, and I'd be more than a bit surprised if anyone really believed it. (I could imagine someone who likes to debate claiming they believed it as a debating tactic, I suppose - and to my view this would be a good time to stop debating and do something constructive). So in my opinion, the confusion arises by taking "zeno time", which is analogous to the Schwarzschild coordinate time "t", too seriously. While it is correct to say that as t-> infinity Alice never reaches the event horizon, just as Achilles never reaches the tortise in zeno time, it still happens. It's just that that event hasn't been assigned a coordinate label. |
| Dec5-12, 05:30 PM | #62 |
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Additionally...
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| Dec5-12, 05:35 PM | #63 |
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| Dec5-12, 05:41 PM | #64 |
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| Dec5-12, 05:44 PM | #65 |
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| Dec5-12, 06:20 PM | #66 |
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I notice that you aren't saying that you *do* postulate a preferred frame, are you in fact doing so? Are you saying that there isn't any other way to save your viewpoint? I'm getting a sort of debate feeling here, with this sudden lack of specificity, with all the "I could" and "I might". |
| Dec5-12, 06:35 PM | #67 |
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| Dec5-12, 06:39 PM | #68 |
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