
#1
Dec612, 02:14 PM

P: 60

Hi im in need of some help for this question:
1+tanx/1tanx = tan(x+(∏/4)) It is easy to solve with the tan trig identites on the right side however, my teacher had told me to do it with SIN and COS only. Im not sure if its possible and was looking for some insight Left Side: Cosx+Sinx/CosxSinx Right Side: End up with {(SinxCos∏/4) + (CosxSin∏/4)}/ (CosxCos∏/4)  (SinxSin∏/4) Can anyone give me some insight? 



#2
Dec612, 02:30 PM

HW Helper
P: 774

A good first step is to replace cos([itex]\pi[/itex]/4) and sin([itex]\pi[/itex]/4) by their actual values.




#3
Dec612, 02:38 PM

P: 60

(Sinx(√2/2)) + (Cosx(√2/2)) / (Cosx(√2/2))  (Sinx(√2/2)) IS there anything i can do? 



#4
Dec612, 02:52 PM

Engineering
Sci Advisor
HW Helper
Thanks
P: 6,352

Math Trig Identities?
Don't get confused by all the notation. This is just the same as simplfying something like
$$\frac{3a + 3b}{3c  3d}$$ 



#5
Dec612, 03:22 PM

P: 60





#6
Dec612, 03:24 PM

P: 60

Nevermind, I feel reallydumb... i got it, thanks guys




#7
Dec612, 03:43 PM

Mentor
P: 21,026

What you wrote is 1 + (tanx)/1  tanx, which is equal to 1. What you meant was (1 + tanx)/(1  tanx). 


Register to reply 
Related Discussions  
Trig identities  Precalculus Mathematics Homework  24  
Trig Identities  Precalculus Mathematics Homework  5  
Re: Trig Identities  Precalculus Mathematics Homework  5  
Trig. Identities  Precalculus Mathematics Homework  3  
trig identities  General Math  3 