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Math Trig Identities? 
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#1
Dec612, 02:14 PM

P: 60

Hi im in need of some help for this question:
1+tanx/1tanx = tan(x+(∏/4)) It is easy to solve with the tan trig identites on the right side however, my teacher had told me to do it with SIN and COS only. Im not sure if its possible and was looking for some insight Left Side: Cosx+Sinx/CosxSinx Right Side: End up with {(SinxCos∏/4) + (CosxSin∏/4)}/ (CosxCos∏/4)  (SinxSin∏/4) Can anyone give me some insight? 


#2
Dec612, 02:30 PM

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P: 943

A good first step is to replace cos([itex]\pi[/itex]/4) and sin([itex]\pi[/itex]/4) by their actual values.



#3
Dec612, 02:38 PM

P: 60

(Sinx(√2/2)) + (Cosx(√2/2)) / (Cosx(√2/2))  (Sinx(√2/2)) IS there anything i can do? 


#4
Dec612, 02:52 PM

Engineering
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Math Trig Identities?
Don't get confused by all the notation. This is just the same as simplfying something like
$$\frac{3a + 3b}{3c  3d}$$ 


#5
Dec612, 03:22 PM

P: 60




#6
Dec612, 03:24 PM

P: 60

Nevermind, I feel reallydumb... i got it, thanks guys



#7
Dec612, 03:43 PM

Mentor
P: 21,216

What you wrote is 1 + (tanx)/1  tanx, which is equal to 1. What you meant was (1 + tanx)/(1  tanx). 


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