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two spaceships in opposite direction at near c |
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| Dec8-12, 07:32 AM | #35 |
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two spaceships in opposite direction at near c![]() Gwelsjr, I really appreciate your effort drawing diagrams. Good job. Unfortunately I am not too happy with your text. The way you explain it is as if the time dilation occurs due to the further dots pacing of clockticks on the clock worldline. There is also a danger of interpreting your diagrams as if timedilation happens because of the taking into account of the lightbeams. Let me put it this way: You have drawn three different diagrams, but to see how timedilation works it is better to look at one diagram only with more information on it. I did it for you: (For simplicity I omited what red says): Blue notices black (and red) time dilation because when his blue clock ticks 15 (not 13 as you wrote;)), in his BLUE frame (=3D spaceworld) the black and red clock show 9. So far so good. Now what black says: Black notices time dilation of blue time because "when his black clock ticks 9 seconds, IN HIS BLACK FRAME (=3D spaceworld) the blue clock is only at 5,399 sec. (9 / 1,6667). And still IN HIS BLACK 3D world the blue 'time dilation' means: red clock is only at 1,975 sec (9 / 4,5556). Here you see clearly that the 'slowing down' of the blue and red clock have NOTHING to with the further spacing of blue or red dots relative to the black dots (red dots are equally spaced as black, blue dots are less spaced relative to the black ones!). On a Loedel diagram (I'm now too lazy too make one) you would see that the time dilation has nothing to do with the further spacing of clock ticks on the worldline of a clock. Time dilation is about relativity of simultaneity. (And that's only possible if you consider all events out there as observer independent entities time indications included (block universe). Just in case you wonder what the reciprocal time dilation is for blue at 9 (see sketch below): in blue 3D space black clock is at 5,389. In blue 3D space when blue clock is at 5,399 the black clock is at 3,238 (= 5,399 : 1,667 ). 3D cuts through 4D block spacetime!
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| Dec8-12, 07:52 AM | #36 |
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Mentor
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| Dec8-12, 08:38 AM | #37 |
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| Dec8-12, 09:23 AM | #38 |
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| Dec8-12, 11:03 AM | #39 |
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I think we might have the same thoughts about this, but to me the whole point about the coordinate systems is that whatever coordinate system you use (apply to the outside observer independent events) then SR's 'relativity of simultaneity' shows you that reality out there is a 4D block spacetime/universe. But this is not allowed to be discussed here.
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| Dec9-12, 06:24 AM | #40 |
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I later drew two more diagrams in response to K^2's request in post #31. In each of these, the signal going from the red spaceship at his 1-minute mark is received by the black spaceship at his 9-minute mark, even though the light signal takes a varying amount of time in each IRF but still travels at c in each of them and not with respect to the speeds of the spaceships. This was the whole point of these diagrams in support of my comment to jartsa in post #29: And now to my main point: The blue spacestation cannot notice the black (or red) spaceship's time dilation. Time dilation is not observable by anyone anywhere anytime. It is a calculation related to the speed of an object in a given IRF. If it were ever observable, then the observer would know which arbitrary IRF we were using. Or, more significantly, if it were observable, then we could identify the an absolute ether rest state and all of Special Relativity would be out the window. Just because I drew three IRF's in which one of the observer's was a rest, you should not extapolate that observer's observations to what is assigned by the IRF, such as the time dilation related to the speed of the other objects. I could just as easily have drawn another diagram in which none of the observers was a rest, for example one in which the black spaceship and the blue spacestation are traveling at the same speed in opposite directions. Then how would you explain time dilation? Look, the reciprocal time dilation is very easily illustrated by looking at each of the IRF's for each observer and my text succinctly states what it is. For example, in the first IRF, blue's rest frame (post #30), I state that gamma for red and black is 1.6667 and I show their dots spaced by that amount with respect to the coordinates which also happens to be with respect to blue since blue is stationary in this IRF. Then if you go to the next IRF, black's rest frame (the first small IRF in post #32), I state in the text that the time dilation for the spacestation (incorrectly identified as the spaceship) is 1.6667 and you can see the exact same spacing of the blue dots in this IRF as you do for the black dots in the first IRF. You can do the same thing for each of the other pairs of space ships/station. |
| Dec9-12, 06:40 AM | #41 |
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For example, in the first IRF (post #30), minute five for the blue spacestation is simultaneous with minute three for the black and red spaceships. However in the other two IRF's (post #32) these three events occur at different coordinate times and so are not simultaneous. But minute three for the blue spacestation is simultaneous with minute five for one or the other of the two spaceships in these other two IRF's. What are you guys concerned with? |
| Dec9-12, 08:06 AM | #42 |
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It's far more correct to explain time dilation by means which clock indication (event) pops up in a selected frame (3D space), whether the dots are spaced or not is besides the point. (That's why a loedel diagram is beter to show time dilation.) The time dilation occurs because the worldlines take a different direction in 4D spacetime, and hence the lines of simultaneity take other directions.... |
| Dec9-12, 06:42 PM | #43 |
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Vandam, I feel like your point was very well placed and fully appropriate to the discussion. Not to take away from the basic point ghwells was making--that was a good response to the original post. But, you certainly brought additional valuable insight to the discussion. Your emphasis on relativity of simultaineity really needed to be presented. It's always good to put the discussion in the context of the foundational physical concepts available to us with special relativity theory.
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| Dec12-12, 09:54 AM | #44 |
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| Dec12-12, 09:14 PM | #45 |
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Beyond that I thought perhaps you may have over emphasized the significance of the derived basis of the "measurement" of time dilation: "And now to my main point: The blue spacestation cannot notice the black (or red) spaceship's time dilation. Time dilation is not observable by anyone anywhere anytime. It is a calculation related to the speed of an object in a given IRF. If it were ever observable, then the observer would know which arbitrary IRF we were using. Or, more significantly, if it were observable, then we could identify the an absolute ether rest state and all of Special Relativity would be out the window." |
| Dec13-12, 06:17 AM | #46 |
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p.s. Vandam also made the very significant observation that for the red and black guys going in opposite directions with the same relativistic speed, the spacing of the minute marks on the two time axes are the same. So, you could not use the spacings to tell you anything at all about time dilation. His emphasis of the use of the hyperplanes of simultaneity was quite appropriate. The hyperplanes of simultaneity are always different in the 4-dimensional universe for any two observers moving with respect to each other. And their space-time diagram minute mark spacings may or may not be the same, depending on the choice of charts used in the diagram. Penrose highlights this even for two observers just walking past each other (his Andromeda Paradox).
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| Dec14-12, 04:02 AM | #47 |
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But then it finally dawned on me. Apparently you and Vandam take the viewpoint that time dilation is calculated based on the relative speed between the clock and the observer, not between the clock and the coordinate time of the IRF. When I said in another thread: |
| Dec14-12, 06:26 AM | #48 |
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Ghwellsjr,
You show us 3 sketches but apparently have big problems of reading my sketch of post #35. No offence, but do you know how to read a 4D Minkowski spacetime diagram? I never said your IRF charts are wrong. But if you would be able to read your 3 charts all in one spacetime diagram only, then you would immediately see what's really going on, in 4D. |
| Dec14-12, 09:44 AM | #49 |
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| Dec14-12, 10:24 AM | #50 |
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Recognitions:
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Vandam, this is a 2D problem. There is no 4D. There is one time dimension and one spacial dimension. A single diagram shows everything that's going on.
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| Dec14-12, 01:29 PM | #51 |
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Let me give you an analogy. A draftsman showes you a bunch of technical drawings. Lots of sheets of paper. Two-dimensional drawings. You say: "Awesome! 2D drawings is what architecture is about. Nothing else." An architect has a glimp at it and says: "The 2D drawings are fine, but... they are all 'only" sections and elevations/façades of a building. The building is reality, your 2D drawings only observations. Let me quickly sketch you the 3D perspective of the house so that you can grasp what you are working on." Draftsman reaction: "All this 3D stuff is ridiculous.' ... Sigh. ![]() But what then happens is even more pathetic: the more the architect explains how it all works, the more the draftsman holds tight on his 2D drawings. But that's normal behavior. Draftsmen are very good technical experts, they protect what they are good at. But they are, or become very seldom good architects. Oh yes, sorry,... architects are probably philosophers, artistic lunatics. Isn't it? (By the way: our two eyes capture 2D images. 2D observations. Are you going to tell me there is no 3D building out there to be observed?) |
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