Register to reply 
Escape velocity and leaving earthby gaIiIeo
Tags: escape velocity 
Share this thread: 
#1
Dec2012, 07:49 AM

P: 2

Need some help with solving bet
Do spacecraft (so we're talking about powered object) have to reach escape velocity in any point of travel to leave earth and if so, can you prove it by any scientific definition ? 


#2
Dec2012, 07:52 AM

Mentor
P: 11,617

No. They could slowly increase their altitude and burn fuel forever  quite inefficient, but it would be possible.



#3
Dec2012, 07:54 AM

P: 2




#4
Dec2012, 08:21 AM

Mentor
P: 11,617

Escape velocity and leaving earth



#5
Dec2012, 12:43 PM

P: 210

To 'escape' from the Earth requires a certain amount of ENERGY (about 63MJ per kg)
If this is supplied as KE then the velocity is about 11km/s. This is what is known as escape velocity. If you wanted to climb up a ladder then 63MJ still need to be supplied but you can take your time. 


#6
Dec2012, 12:59 PM

Emeritus
Sci Advisor
PF Gold
P: 2,361

But to be fair, escape velocity decreases with altitude. So if you leave Earth at just 1 km/sec, when you get to about twice as far away as the Moon, the escape velocity from there will have dropped to 1 km/sec.



#7
Dec2012, 01:13 PM

P: 210

To be totally fair
The original question related to escape velocity from the Earth. It is a mistake to see this as a discussion about VELOCITY. To escape from the Earth requires ENERGY. If all of this energy (63MJ/kg) is supplied in one go then the velocity required is 11km/sec. If, lets say 3MJ can be supplied by climbing to the top of a ladder, then 60Mj need to be provided as KE ie a velocity of 10.9km/sec 


#8
Dec2012, 04:21 PM

HW Helper
P: 7,048

Assuming a finite exhaust velocity and a finite ratio of (mass of fuel) / (mass of spacecraft), eventually you'll run out of fuel (update based on mfb's next post  unless you can use increasingly less fuel so that total fuel usage approaches some finite amount as time approaches infinity). At this point the rocket will need to have achieved the escape velocity required for that distance from the earth, but at very large distances, the escape velocity will be very small. Energy wise, this is very inefficient. It's better to focus on increasing velocity by methods that don't directly oppose gravity (although the increase in velocity will result in a curved path that moves away from the earth). 


#9
Dec2012, 05:12 PM

Mentor
P: 11,617

The most efficient way is to reach escape velocity as quickly as you can, I agree. 


#10
Dec2012, 06:40 PM

HW Helper
P: 7,048




#11
Dec2112, 06:49 AM

P: 907

Of course, this ignores the problem of air resistance (which motivates a slower and more vertical launch), the practical limitations on how fast you can burn fuel (the faster you burn it, the bigger your engines and your engines are not payload) and the possibility of a gravitational slingshot. If you are operating under the constraint that you are not allowed to actually reach escape velocity then an infinitesimal nudge to this thrust profile with a massive impulse at the start and a decreasing trickle of thrust later on will work. Clearly, for every such thrust profile there is another one that is just a bit better because it decreases that trickle just a tad more. It follows that there no _optimal_ trajectory that stays below escape velocity. 


Register to reply 
Related Discussions  
Velocity and leaving earth's atmosphere  General Physics  4  
How would I calculate the escape velocity from the earth?  Introductory Physics Homework  3  
Gravitation & Escape Speed  Stone leaving Earth and reached the Moon.  Introductory Physics Homework  32  
Escape velocity from center of earth  Classical Physics  7  
Why is the escape velocity of Earth so fast?  General Physics  6 