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On the nature of the "infinite" fall toward the EH |
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| Dec22-12, 04:24 PM | #409 |
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On the nature of the "infinite" fall toward the EH |
| Dec22-12, 10:27 PM | #410 |
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Quote by Austin0 View Post
Yes I am aware it is a part of the classical paradox as I mentioned in my initial post frame of the ground. I.e. Zeno coordinates. Do you disagree??? What other possible frame for such a statement do you propose??? So when Pervect redefines Achilles velocity as non-uniform in the Zeno frame it is now ,not necessarily a logical conclusion that Achilles velocity is constant in any other frame, as no other frame was defined . So if Achilles is in non- uniform motion (accelerating) as measured in the Zeno frame how do you propose that it is measured as uniform (inertial) in any one of those other inertial frames??? So what is the basis ,in the classical description, for your assumption of constant velocity for Achilles ? What unspecified inertial frame ??? Without a valid basis for an assumption of constant velocity there is no basis for calculating a different time rate for Achilles either, is there??? I certainly never thought for a moment there was deception on Pervects part. OTOH wouldn't you agree that the original is easily and unambiguously falsified by empirical demonstration? As simple as getting up and catching up to a friend. Wouldn't you also agree that creating an association between the two cases seems to imply that the Sc case is equally unambiguously false?? But isn't the amended Zeno case now as unfalsifiable in the real world as the Sc scenario??? As ambiguous?? Do you think that if Achilles started out in Zeno's time with Pervect's conditions he would have caught the tortoise by now in our frame (Zeno coordinates)?? |
| Dec23-12, 01:34 AM | #411 |
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Look, Pauli exclusion principle says that no two identical fermions can occupy the same quantum state. It does not tell us what would happen if two identical fermions would try to occupy the same quantum state. Currently we have no idea why the nature behaves that way. And there is still some room for interpretation. QM gives quite abstract definition for "quantum state". From wikipedia article about quantum state: "In quantum physics, quantum state refers to the state of a quantum system. A quantum state is given as a vector in a vector space, called the state vector." Well, we consider particles to be physical entities but quantum state is defined as mathematical entity. So it seems that Pauli exclusion principle is not very rigorous. This leaves (at least for me) the question open how we should model quantum state in real space (space-time). |
| Dec23-12, 01:43 AM | #412 |
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| Dec23-12, 06:58 AM | #413 |
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| Dec23-12, 07:38 AM | #414 |
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[tex]ds^2=-c^2 \left( \frac{(100-vt) ln(2)}{v} \right)^2 dn^2 + dx^2 + dy^2 + dz^2[/tex] This metric is clearly different from the metric in an inertial frame. However, let's be careful about exactly the way in which the original is false. The original is correct in its description of all events up to (but not including) the event where Achilles catches up with the turtle. Where it fails is if it asserts anything about events at or beyond that point. Similarly with SC, SC is correct in its description of all events up to (but not including) the EH. Where it fails is if it asserts anything about events at or beyond the EH. |
| Dec23-12, 09:24 AM | #415 |
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| Dec23-12, 09:53 AM | #416 |
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| Dec23-12, 12:28 PM | #417 |
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Actually, even that is not really the right way to say it. The Pauli exclusion principle as we have stated it is not a fundamental law; the fundamental law is that fermion wave functions are antisymmetric under particle exchange, whereas boson wave functions are symmetric. If I have a boson, say a spin-0 particle, at spacetime position x, and another spin-0 particle of the same particle type at spacetime position y, the wave function is symmetric under exchange of those two particles. But if I have a fermion in a definite spin state, say a spin-up electron, at spacetime position x, and another spin-up electron at spacetime position y, the wave function is antisymmetric (i.e., it changes sign) under exchange of those two particles. The Pauli exclusion principle, which says that the wave function is identically zero if x = y, is an obvious consequence of the antisymmetry. However, it's not the only consequence; another consequence is that as x and y get closer together, the amplitude of the wave function decreases. That's what causes degeneracy pressure. But all of that is below the level that GR models anyway. GR doesn't care about the microscopic details of matter; all it cares about is the stress-energy tensor. Degeneracy pressure, from the standpoint of the stress-energy tensor, works just like any other kind of pressure. The only real difference is the equation of state, i.e., the relationship between pressure and energy density. |
| Dec24-12, 01:55 AM | #418 |
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Your assumptions seems to be that particles affect occupancy of quantum levels only over short distance. I assume that occupancy of quantum level drops as inverse square law as we go further from the particle. |
| Dec24-12, 05:14 AM | #419 |
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| Dec24-12, 07:33 AM | #420 |
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I.e. your assumption "Formation of EH relies on idea that gravitating object can get more compact" is not correct. The formation of the singularity relies on that, but not the EH. The EH can form with simply a very large amount of non-compact material and you do not need a singularity in order to obtain an EH. So again, what would prevent the formation of the EH? Degeneracy won't do it, that would only prevent the formation of the singularity. |
| Dec24-12, 10:51 AM | #421 |
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| Dec24-12, 11:27 AM | #422 |
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| Dec25-12, 01:42 AM | #423 |
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First, we can add more matter to given gravitating object while it's radius is not increased too much by this addition. Second, we can make given gravitating object more compact while it's mass is not reduced too much by this compactification. I guessed that you was talking about the second scenario. If you are considering first scenario and want arguments concerning this scenario in particular please say it so that I don't have to guess. |
| Dec25-12, 01:44 AM | #424 |
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| Dec25-12, 02:02 AM | #425 |
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So what I say is that if we have two fairly degenerate stars approaching each other then whey would melt first and after that will start to evaporate. Or alternatively will fall into pieces depending on homogeneity of star. If particles can't remain in their quantum states they can't maintain their collective structure. Kind of obvious IMO. |
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