## Pendulum clock when taken to moon

1. The problem statement, all variables and given/known data
A pendulum clock that keeps correct time on the earth is taken to the moon. It will run

a) at correct rate
b)6 times faster
c)√6 times faster
d)√6 times slower

2. Relevant equations

3. The attempt at a solution
$T_{earth} = 2\pi \sqrt{\dfrac{L}{g}} \\ T_{moon} = 2\pi \sqrt{\dfrac{L}{g/6}}$

Dividing i) by ii)

$\dfrac{T_{earth}}{T_{moon}} = \frac{1}{√6} \\ T_{moon} = √6T_{earth}$

This implies option c) is correct but my book says it is option d).
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 Recognitions: Gold Member The period is longer so the frequency must be...

Recognitions:
Gold Member
 Quote by utkarshakash 1. The problem statement, all variables and given/known data A pendulum clock that keeps correct time on the earth is taken to the moon. It will run a) at correct rate b)6 times faster c)√6 times faster d)√6 times slower 2. Relevant equations 3. The attempt at a solution $T_{earth} = 2\pi \sqrt{\dfrac{L}{g}} \\ T_{moon} = 2\pi \sqrt{\dfrac{L}{g/6}}$ Dividing i) by ii) $\dfrac{T_{earth}}{T_{moon}} = \frac{1}{√6} \\ T_{moon} = √6T_{earth}$ This implies option c) is correct but my book says it is option d).
Use concept ,

T $\alpha$ 1/√g

As √g reduces by √6 on moon , this implies time period on moon will be √6 times that of earth , as you got. You interpreted your answer wrongly. If the time period increases , pendulum will oscillate slower or faster for a given displacement of the bob ?

## Pendulum clock when taken to moon

 Quote by sankalpmittal Use concept , T $\alpha$ 1/√g As √g reduces by √6 on moon , this implies time period on moon will be √6 times that of earth , as you got. You interpreted your answer wrongly. If the time period increases , pendulum will oscillate slower or faster for a given displacement of the bob ?
Thanks for pointing out my mistake

Recognitions:
Gold Member
 Quote by utkarshakash [b] This implies option c) is correct but my book says it is option d).
Forget the math for a minute and just think about it logically. Would you really expect a pendulum clock when moved to lower gravity to have the pendulum swing FASTER? Really ?

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