# Pendulum clock when taken to moon

by utkarshakash
Tags: clock, moon, pendulum
 P: 542 1. The problem statement, all variables and given/known data A pendulum clock that keeps correct time on the earth is taken to the moon. It will run a) at correct rate b)6 times faster c)√6 times faster d)√6 times slower 2. Relevant equations 3. The attempt at a solution $T_{earth} = 2\pi \sqrt{\dfrac{L}{g}} \\ T_{moon} = 2\pi \sqrt{\dfrac{L}{g/6}}$ Dividing i) by ii) $\dfrac{T_{earth}}{T_{moon}} = \frac{1}{√6} \\ T_{moon} = √6T_{earth}$ This implies option c) is correct but my book says it is option d).
 PF Gold P: 1,054 The period is longer so the frequency must be...
P: 700
 Quote by utkarshakash 1. The problem statement, all variables and given/known data A pendulum clock that keeps correct time on the earth is taken to the moon. It will run a) at correct rate b)6 times faster c)√6 times faster d)√6 times slower 2. Relevant equations 3. The attempt at a solution $T_{earth} = 2\pi \sqrt{\dfrac{L}{g}} \\ T_{moon} = 2\pi \sqrt{\dfrac{L}{g/6}}$ Dividing i) by ii) $\dfrac{T_{earth}}{T_{moon}} = \frac{1}{√6} \\ T_{moon} = √6T_{earth}$ This implies option c) is correct but my book says it is option d).
Use concept ,

T $\alpha$ 1/√g

As √g reduces by √6 on moon , this implies time period on moon will be √6 times that of earth , as you got. You interpreted your answer wrongly. If the time period increases , pendulum will oscillate slower or faster for a given displacement of the bob ?

P: 542

## Pendulum clock when taken to moon

 Quote by sankalpmittal Use concept , T $\alpha$ 1/√g As √g reduces by √6 on moon , this implies time period on moon will be √6 times that of earth , as you got. You interpreted your answer wrongly. If the time period increases , pendulum will oscillate slower or faster for a given displacement of the bob ?
Thanks for pointing out my mistake
PF Gold
P: 5,448
 Quote by utkarshakash [b] This implies option c) is correct but my book says it is option d).
Forget the math for a minute and just think about it logically. Would you really expect a pendulum clock when moved to lower gravity to have the pendulum swing FASTER? Really ?

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