|Jan28-13, 07:09 PM||#1|
how do you "indicate transient terms" when y just equals 1 ?
t is the dependent variable in this problem and I'm told to "indicate transient terms". Well, t=1 so is this a trick question or did I do something wrong?
|Jan28-13, 08:04 PM||#2|
You seem to have forgotten the "constant of integration". t= 1 is one function satisfying this equation. There are others, involving terms that go to 0 as t goes to infinity.
|Jan28-13, 08:16 PM||#3|
ok, so t = 1 + c
or t = 1 + c/μ ?
Because the c term should've actually been introduced on the 2nd to last line. If that's true, that e^((e^x^2)/2) function should've also been divided by c when solving for t.
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