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How do you indicate transient terms when y just equals 1 ?by Jeff12341234
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#1
Jan2813, 07:09 PM

P: 179

t is the dependent variable in this problem and I'm told to "indicate transient terms". Well, t=1 so is this a trick question or did I do something wrong?



#2
Jan2813, 08:04 PM

Math
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Thanks
PF Gold
P: 39,317

You seem to have forgotten the "constant of integration". t= 1 is one function satisfying this equation. There are others, involving terms that go to 0 as t goes to infinity.



#3
Jan2813, 08:16 PM

P: 179

ok, so t = 1 + c
or t = 1 + c/μ ? Because the c term should've actually been introduced on the 2nd to last line. If that's true, that e^((e^x^2)/2) function should've also been divided by c when solving for t. 


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