how do you "indicate transient terms" when y just equals 1 ?


by Jeff12341234
Tags: equals
Jeff12341234
Jeff12341234 is offline
#1
Jan28-13, 07:09 PM
P: 179
t is the dependent variable in this problem and I'm told to "indicate transient terms". Well, t=1 so is this a trick question or did I do something wrong?


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HallsofIvy
HallsofIvy is offline
#2
Jan28-13, 08:04 PM
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PF Gold
P: 38,894
You seem to have forgotten the "constant of integration". t= 1 is one function satisfying this equation. There are others, involving terms that go to 0 as t goes to infinity.
Jeff12341234
Jeff12341234 is offline
#3
Jan28-13, 08:16 PM
P: 179
ok, so t = 1 + c
or t = 1 + c/μ ?
Because the c term should've actually been introduced on the 2nd to last line. If that's true, that e^((e^x^2)/2) function should've also been divided by c when solving for t.


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