# Free Body Diagram

by ThePhysicsBoy
Tags: body, diagram, free
 P: 10 1. The problem statement, all variables and given/known data A cavewoman is dragging her 65.4 kg mate home, up a gentle 10° incline. The co efficient of friction for skin on oil is 0.40. What is the minimum applied force she needs to keep the neanderthal moving with uniform motion? 2. Relevant equations ff=μFn fg=mg fnet=ma 3. The attempt at a solution I tried solving for Ff using ff=μFn but I don't have the Fn do I? We have gravity going down which is -9.8(65.4)=640.92...would that be the force of normal?
 P: 10 f=ma I have mass but not acceleration? How would i calculate it?
 P: 10 so...fa=65.4(0)...?
 P: 10 Free Body Diagram it does not..thats my problem :S
 P: 10 :/ Are you sure lol? I am pretty sure he prof wouldn't give a question thats not solveable
 P: 10 ah alright, so prof musta made a mistake. Thanks, Got an exam tommorow though :P hope he doesnt put this question on it
 P: 10 school in Calgary :P
 Sci Advisor HW Helper Thanks PF Gold P: 5,259 The professor didn't make a mistake. You already calculated the force of gravity acting on the guy. For a slope of 10 degrees, what are the components of this force in the directions perpendicular and parallel to the incline? What direction does the force parallel to the incline point (up the incline, or down the incline)? If she is trying to pull the guy up the incline, what frictional force does she have to overcome? Make a list of the forces acting on the guy parallel to the incline. How many forces are there? According to the problem statement, is the guy accelerating up the incline, or is he just barely moving at a constant speed? Chet
 P: 10 - Frictional Force, Moving towards the left - Force applied going [E 10 N] - Force of Gravity Down - Force of Normal Up Since it says gently, I assume it is moving at a constant velocity? or close to? What is the next step after Force of gravity? Thanks for replying Chet
 Sci Advisor HW Helper Thanks PF Gold P: 5,259 The gravitational force acting on the guy can be resolved into two components, one perpendicular to the incline and the other parallel to the incline. What are the numerical values of these two components?
 P: 10 component y = -9.7? Component x = Force of friction ? That is the only force acting in the x direction isn't it?
 P: 10 I can't figure it out :/
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 Quote by ThePhysicsBoy component y = -9.7? Component x = Force of friction ? That is the only force acting in the x direction isn't it?
What do you mean by "the x direction"? If that is along the surface of the incline, then there is a force in addition to friction acting in the x direction, namely gravity. Gravity has a component along the incline.