# Find q for a moving particle

by Rae_4
Tags: electricity
 P: 4 1. The problem statement, all variables and given/known data A moving particle encounters an external electric field that decreases its kinetic energy from 8560 eV to 6770 eV as the particle moves from position A to position B. The electric potential at A is -50.5 V, and the electric potential at B is +25.9 V. Determine the charge of the particle. Include the algebraic sign (+ or −) with your answer. 2. Relevant equations V=EPE/q, EPE=qEx=KE 3. The attempt at a solution ΔKE/ΔV=q 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution
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P: 11,683
 Quote by Rae_4 1. The problem statement, all variables and given/known data A moving particle encounters an external electric field that decreases its kinetic energy from 8560 eV to 6770 eV as the particle moves from position A to position B. The electric potential at A is -50.5 V, and the electric potential at B is +25.9 V. Determine the charge of the particle. Include the algebraic sign (+ or −) with your answer. 2. Relevant equations V=EPE/q, EPE=qEx=KE 3. The attempt at a solution ΔKE/ΔV=q
Hi Rae_4, Welcome to Physics Forums.

Did you have a particular question about the problem? You seem to be on the right track with your attempt.
 P: 4 Yeah. I'm trying that formula, but it keeps telling me my answer is incorrect. I'm not sure what I'm doing wrong. When I attempt the practice version it is trying to tell me the answer is times 10^-18 and nothing I have in that formula would give me a number that small. Are my formulas incorrect?
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